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几何体的体积表面积计算-geometric size of the surface area calculation

jQuery 实现了 图片远处放大效果，非常之炫的德德的恩德-jQuery to achieve the image distance amplification effect, very flashy Dede" s Ende

ARCGIS ENGINE+ACCESS数据库开发的一套GIS系统，本人的毕业设计-ARCGIS ENGINE+ ACCESS database developed by a GIS system, my graduation design

马跳棋盘源程序 ,一个实际问题的解决-Ma checkerboard source, a practical solution to the problem

高精度数控电源制作,数码显示，带原理图和固件程序-CNC high-precision power production, digital display, with schematics and firmware

检查 C 源码中括号的匹配性-check C source code compatibility brackets

学习字幕的制作的好动！ 都来看看！diy友不要错过！-subtitles study the production of active! Look at all! DIY-you should not miss!

The Microsoft® Cryptographic Application Programming Interface (CryptoAPI) provides services that enable application developers to add authentication, encoding, and encryption to their Microsoft Win32® -based applications. Application developers can use the functions in the CryptoAPI without knowing anything about the underlying implementation, in much the same way as they can use a graphics library without knowing anything about the particular graphics hardware configuration.-The Microsoft® Cryptographic Application Programming Interface (CryptoAPI) provides services that enable application developers to add authentication, encoding, and encryption to their Microsoft Win32®-based applications. Application developers can use the functions in the CryptoAPI without knowing anything about the underlying implementation, in much the same way as they can use a graphics library without knowing anything about the particular graphics hardware configuration.

利用循环卷积和线性卷积之间的关系，用FFT和IFFT的现有程序实现信号线性卷积快速实现-cyclic and linear convolution convolution of the relationship between FFT and IFFT with the existing procedures of linear convolution signal Fast

约瑟夫问题是一个经典的问题，我们不妨将这个经典问题进行扩展，变成一个双向的约瑟夫问题。 已知n个人（不妨分别以编号1，2，3，…，n 代表 ）围坐在一张圆桌周围，首先从编号为 k 的人从1开始顺时针报数，1, 2, 3, ...，记下顺时针数到 m 的那个人，同时从编号为 k 的人开始逆时针报数，1, 2, 3, ...，数到 m 后，两个人同时出列。然后从出列的下一个人又从 1 开始继续进行双向报数，数到m的那两个人同时出列，…；。依此重复下去，直到圆桌周围的人全部出列。直到圆桌周围只剩一个人为止。  　　如果双向报数报到 m 时落在同一个人身上，那本次出列的只有一个人。 请点击左侧文件开始预览 ！预览只提供20%的代码片段，完整代码需下载后查看 加载中 侵权举报