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Ericsson_MMSAPI 爱立信彩信应用开发接口介绍
Ericsson_MMSAPI 爱立信彩信应用开发接口介绍-Ericsson_MMSAPI Ericsson MMS application development interface introduced
- 2022-02-01 10:58:46下载
- 积分:1
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it is a matlab book that a guide for the beginner and experience user.
it is a matlab book that a guide for the beginner and experience user.
- 2022-08-16 21:16:23下载
- 积分:1
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富士通单片机C语言手册,中文版,针对富士通MCU
富士通单片机C语言手册,中文版,针对富士通MCU-Fujitsu single-chip C language manual, the Chinese version for Fujitsu MCU
- 2022-05-22 04:31:42下载
- 积分:1
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门诊收费管理系统,欢迎大家下在
门诊收费管理系统,欢迎大家下在-Out-patient charges for management systems, welcomed everyone in
- 2022-07-01 04:57:05下载
- 积分:1
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Viterbi编码是非常好的。在linux下运行
viterbi code is very good. run in linux
- 2022-08-19 01:17:07下载
- 积分:1
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GPIO (General Purpose Input and Output ports) with microprocessor programmable t...
GPIO (General Purpose Input and Output ports) with microprocessor programmable tri-state bus interface-Use verilog to design a 48 control points that can be programmed to input or output controller
- 2022-12-18 05:15:02下载
- 积分:1
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相关的销售服务管理行业的一个软件,与上次上传的是一个体系...
相关的销售服务管理行业的一个软件,与上次上传的是一个体系-related to the sale of service management software industry, with the last upload system is a
- 2023-06-25 13:30:09下载
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图书馆借阅系统建模 含rational rose完成的各种建模图的事例
图书馆借阅系统建模 含rational rose完成的各种建模图的事例-Library system modeling rational rose with the completion of the various modeling examples of Figure
- 2022-02-10 10:13:25下载
- 积分:1
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JAVA 2平台安全技术
JAVA 2平台安全技术-结构,API设计和实现-Java 2 Platform security technology-structure, API Design and Implementation
- 2022-01-20 23:21:45下载
- 积分:1
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C 计算器代码
/ * mustafasırrıinci * /
#include < stdio.h >
#include < stdlib.h >
#include < math.h >
int main ()
{
浮 int1 int2,结果 ;
char 操作 ;
printf("CALCULATORn") ;
开始:
printf ("nnEnter 两个整数 please.n") ;
printf("1.integer:") ;
scanf ("%f"& int1) ;
printf("2.integer:") ;
scanf ("%f"& int2) ;
选择:
printf ("nenter 操作的符号。") ;
printf ("naddition: + nsubtraction:-nmultiplication: * ndivision: /nexponention: ^ nto 退出:! n") ;
scanf ("%s"& 操作) ;
虽然 (操作! = "!")
{
switch(operation)
{
案件 "+":
结果 = int1 + int2 ;
打破 ;
案件 "-":
结果 = int1-int2 ;
打破 ;
案件 " *":
结果 = int1 * int2 ;
打破 ;
- 2022-08-13 04:26:33下载
- 积分:1