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用C++实现的简易终结者小游戏,可以运行, 不过功能很简单
用C++实现的简易终结者小游戏,可以运行, 不过功能很简单-C++ implementation of the simple Terminator game
- 2022-02-14 08:49:25下载
- 积分:1
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用来检查文件之间的相似程度
用来检查文件之间的相似程度-used to check the documents of the similarity between the
- 2022-02-15 03:01:12下载
- 积分:1
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一个小程序, 大家看看吧
一个小程序, 大家看看吧-a small program, we look at it
- 2022-03-23 20:03:18下载
- 积分:1
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In this case the compiler for each file is the order: 17_parity.vhd 17_test_benc...
本例对各个文件进行编译的顺序是:
17_parity.vhd
17_test_bench.vhd-In this case the compiler for each file is the order: 17_parity.vhd 17_test_bench.vhd
- 2022-02-25 07:43:38下载
- 积分:1
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邮票问题:设一国家发行n种不同面值的邮票,并且每封信至多允许贴m张邮票,对于给定的m,n值,写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连...
邮票问题:设一国家发行n种不同面值的邮票,并且每封信至多允许贴m张邮票,对于给定的m,n值,写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连续区域以及获得这个区域的各种可能面值的集合。如,当 n=4,m=5,若有面值为(1,4,12,21)的四种邮票,则邮资最大的连续区域为1到71。还有其他面值的四种邮票可组成同样大小的区域吗-stamp issue : Let a national issue n different denominations of the stamps and letters each allow up to m stamp affixed, to the m, n, write an algorithm derived from a postage in an increment of the circumstances, may obtain a postage value of the maximum continuous access to this region and regional various denominations could assemble. For example, when n = 4, m = 5, if the values of (1,4,12,21) of the four stamps, postage largest regional consecutive 1-71. There are four other denominations of the stamps can be the same size as the composition of the region? ?
- 2022-02-24 19:12:53下载
- 积分:1
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串行通信键控步进电机系统 mega128的
丛书上光盘里的
串行通信键控步进电机系统 mega128的
丛书上光盘里的-Serial Communication keying mega128 stepper motor system of the series on CD-ROM
- 2022-08-06 14:01:35下载
- 积分:1
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数值分析要求:第二题编成命令文件即可,其中阶乘可以单独编成函数文件在命令文件中调用,也可以直接在你所编的命令文件中利用循环语句直接计算;
第四题编成通用的...
数值分析要求:第二题编成命令文件即可,其中阶乘可以单独编成函数文件在命令文件中调用,也可以直接在你所编的命令文件中利用循环语句直接计算;
第四题编成通用的程序,建议编成函数文件。提示:可以把多项式的系数和所需要求解的点设为参数。-Numerical Analysis of requirements: the second title of the command file can be compiled, which can factorial function into a separate file in order to call the document can also be made directly in your document, use the command loop direct calculation into fourth title common procedures, the proposed document into function. Tip: polynomial coefficients can be requested and the required parameters set point solution.
- 2022-01-25 22:12:15下载
- 积分:1
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虚拟仪器的232通讯程序,安装了Labview的直接可以用了
虚拟仪器的232通讯程序,安装了Labview的直接可以用了-Virtual instrument 232 the communication process, the installation of Labview can be used directly
- 2022-02-07 22:41:47下载
- 积分:1
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beereader source code
beereader source code
- 2023-02-24 00:40:03下载
- 积分:1
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自己编的赛马程序
自己编的赛马程序-own series of the Jockey Club procedures
- 2022-02-21 12:43:36下载
- 积分:1