一个好用的增强型文件搜索工具，可以指定目录搜索，搜索…

强力文本搜索器,指定目录和文件类型, 即可搜索特定文本字串,适合C++源代码 查看和查找 附带程序 -powerful text search engine, designated directories and file types, we can search for specific text strings, for C source code view and search incidental proceedings

webgui,嵌入HTML页面-webgui, embedded HTML page ...................

我的毕业设计经典的模拟1990坦克，代码全部自己写的，非常有参考价值，想学习做简单游戏的可以从这学起~~~鄙视抄袭。。。源代码仅仅做参考用-I graduated from the simulation of the classic 1990 design tanks, all of its own written code, very useful, want to learn the game can be so simple to learn from ~ ~ ~ despise plagiarism. . . Only a reference source by ~ ~ ~

通讯录，简单的C语言程序，本人的处女作~~~呵呵，希望大家支持我 -Address book, a simple C language program, my debut ~ ~ ~ Oh, I hope you will support me

VC++编程，有源代码，本程序是改进的加密压缩存档类-VC++ Programming, source code, the program is to improve the types of encryption-extracting archive

TSR 驻留程序的演示 　 TSR 驻留程序的演示 　-TSR program demonstrates the presence of

资源描述通过贴图换肤技术实现自己想要的界面，本例为通用代码，需要更漂亮的界面用户可以自己用phtoshop设计漂亮的界面图片进行更换

主是一个哈夫曼树生成过程的程序，采用Borland C++编写，界面友好，运行结果正确！-Lord is a Huffman tree generation process procedures, the use of Borland C++ Prepared, friendly interface, the correct results!

--作品所有源代码(100％能运行)和开发文档 贝壳工作室---发票管理系统其中包括： 1.租凭业发票 2.建筑业发票 3.固定资产发票 4.服务行业发票 5.无形资产发票 这是于2004年编写，前面已经发布过两套类似发票管理系统源代码 这个是最新版，我将完全公布其所有源代码和程序。如果遇到什么 问题请与我联系：贝壳工作室网址:http://www.bkwork.cn-- works all the source code (100 to run) and the development of shellfish Studios--- invoice document management system including: 1. Lease industry invoice 2. Construction invoices 3. Fixed asset invoices 4. Service industry invoice 5. intangible invoices that are prepared in 2004, have already issued two sets of Invoice Management System similar to source code this is the latest version, I will be fully released all of its source code and procedures. If you have any questions, please contact me: Shell Studios website: http://www.bkwork.cn

编写一个函数，输入n为偶数时，调用函数求1/2+1/4+...+1/n,当输入n为奇数时，调用函数1/1+1/3+...+1/n(利用指针函数)-The preparation of a function, type n is an even number, the call function for 1/2+1/4+...+ 1/n, when n is odd input, call function 1/1+1/3+...+ 1/n (use pointer function)