用c++做的图书馆管理系统，英文界面 功能包括注册 借书 还书 书本登记等...

Professional Uml With Visual Studio Net - Unmasking Visio For Enterprise Architects Code.zip-Professional Uml With Visual Studio Net- Unmasking Visio For Enterprise Architects Code.zip

ds13b20 与大家分享,呵呵^^^^^^^^^^^^ 请大家指教!-ds13b20 to share with you, huh, huh ^^^^^^^^^^^^ advice please everyone!

通用WAP网站生成系统(PowerDiamond) v.1 -GM WAP site generation system (PowerDiamond) v. 1

本程序为检测16路输入45~65HZ的信号，并按每路状态输出各自想应路信号-This procedure for the detection of 16 of 45 ~ 65HZ input signal, and the way each state would like to output their signals should be

本tkyc使用Quick VxD 生成了一个动态加载的“Hello world”VxD框架，并通过一个WIN32应用程序完成VxD的加载和卸载。在应用程序中，制作２个按钮，一个用于加载VxD,另一个用于卸载VxD。在VxD被动态加载时，VxD会输出数据流“Hello world!”以及“动态加载dynamic.vxd成功”；在VxD被卸载时，VxD会输出数据流“动态卸载dynamic.vxd成功”。-tkyc use of the Quick VxD to generate a dynamic loading of the "Hello world "VxD framework and through a Win32 application procedures are completed VxD loading and unloading. In the application process, the production of two buttons, a VxD for loading, unloading for another VxD. In VxD dynamically loaded, VxD will output data stream "Hello world!" and "dynamic loading dynamic.vxd successful "; in VxD be unloaded, VxD will output data stream "dynamic unloading dynamic.vxd success."

reddy snr estimator. run the interleaver file first than run the estimator file and get the results.

汉诺塔游戏 好久没动手写过东西了，练习的东东，还有很多问题，适合初学者学习，代码里有注释。 -HANOR hands game had not written anything, the Eastern practice, there are many problems, for beginners learning, there are code Notes.

This is an extension of sign example. You can design your own traffic sign by using Verilog. And the result from Verilog can be seen by the attached C file.

某公司的生产销售管理系统源代码.vc++环境.access数据库,需要设置数据源.是相当专业的行业软件.要下的动作快!-a company in the production and sale of the source code management system. Vc environment. Access databases, the need for data sources. is a professional software industry. to the fast action!

排列问题 M个1,N个0的排列(高效率版) 排列数为:c(m+n,n) 对n个0,m个1,我的想法是这样的: 每个排列可以分三段: 全0列,全1列, 子问题列 设各段长:r,s,t .子问题列就是 (n,m) = (n-r,m-s),其中0