android获取（采集）网络图片的例子

这是一部制作精良的中国象棋小游戏,画面清新，操作简单是它的优势，电脑的难度不是很高，所以初学者也可以试试啦~ -This is a well-made Chinese chess game, the screen clean, simple operation is its advantage, the computer is not very high degree of difficulty, so beginners can also try啦~

javascript教程上部分-javascript partly Guide

enigma源码，可以给刚开始学的人学习下。

弹力球游戏,c++开发，比较简单的，对初学者学习很有帮助-ball game,by C++

基于内容的图像检索，博士毕业学位论文，搞这方面的可以-content-based image retrieval, Dr. graduate thesis and engage in this area can s

matlab拉冬变换程序，包括拉冬正变换和反变换程序。-Matlab Radon transform procedures, including Radon transformation and anti-transformation process.

华为DTU拨号全过程，帮助学习GPRS的同学以及开发人员，相当的有用处

Asp.net水晶报表(CrystalReports)及柱状图源码实例大全,这些源码例子实现了水晶报表的查看、柱状图显示、打英导出、缩放等基本功能，如果想了解更多比如利用DataSet方式、Push、Pull等模式，那就需要自己更深一步的研究了，难得的Asp.net2.0水晶报表源码。

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.