lcd12864控制时钟，可以定时温度显示等功能

java 建造模式，JavaMail中最重要的一种模式，包括例子。-java construction mode, the most important JavaMail a model, including examples.

用C++来实现BP神经网络的功能，进行土地预测。-C++, to achieve the BP neural network functions, land forecasts.

labview的授权VI 1、打开“授权许可文件生成”，并运行 2、打开许可验证，可查看剩余使用权限 3、发现错误运行“调试差错程序）-LabVIEW authorization VI1, open the

一:需求分析 1．本程序需掌握树和二叉树的概念及工作原理，运用其原理及概念完成实验.。 2．问题描述： 一个逻辑表达式如果对于其变元的任一种取值都为真，则称为重言式；反之，如果对于其变元的任一种取值都为假，则称为矛盾式；然而，更多的情况下，既非重言式，也非矛盾式。试写一程序，通过真值表判断一个逻辑表达式属于那一类。 3．基本要求： （1）逻辑表达式从终端输入，长度不超过一行。逻辑运算符包括“|”，“&”和“~”, 分别表示或、与和非，运算优先程度递增，但可以有括号改变，即括号内的运算优先。逻辑变元为大写字母。表达式中任何地方都可以含有多个空格符。 （2）若是重言式或矛盾式，可以只“显示True forever”或“False forever”，否则显示“Satisfactible”以及变量名序列，与用户交互。若用户对表达式中变元取一组值，程序就求出并显示逻辑表达式的值。 -1 : a needs analysis. The process required the trees and the binary tree master the concept and principle, to use its principles and the concept of completion of the pilot. . 2. Problem description : If a logical expression for the changes in the yuan"s value for a true, as tautology; Instead, If the changes for the yuan"s value for a fake, then called the contradiction; However, the more the situation, neither tautology. is not a contradiction. Try to write a procedure for the adoption of a truth table judgment logical expression belong into that category. 3. Basic requiremen

基于vc++的有关摄影测量中近似垂直摄影情况下空中后方交会求解的源代码-based on the photographic measurement of the approximate vertical aerial photography Resection Solving the source code

扫描线算法中的一种,在vb下运行,比较好用-scan lines of an algorithm, vb running, the better quality

It about c++ senior traing course. it very usefull for someone who want to enhance c++ programing. it comes frome hua wei company s traning course

改程序描述了，在vs中数据库的一系列的用法，重数据库的链接，数据库的创建，数据库的访问和数据库视图的建立，数据库修改等基本的过程。不愧为学习数据库的好例子。-Change procedure described in the series vs the usage of the database, re-link to the database, database creation, database access and database view creation, database, modify the basic process. Worthy of study and a good example of the database.

游戏规则 目的：在本游戏中，你将作为一名裁缝，将尽可能多的纽扣穿成 一个闭合的路线。游戏初始有 15 个纽扣，随着时间的增 加，纽扣数目也增加，当达到70个时游戏即结束。 规则：只能在有纽扣的点穿线，且只能在水平方向或竖直方向穿 线。线可交叉，但有纽扣的点不能交叉连接。 秘诀：要尽可能使连线长且该连线上的纽扣数多。-Rules of the game Objective: In this game, you will serve as a tailor, will be wearing buttons as much as possible into a closed line. The initial game there are 15 buttons, as time increases, the number of buttons has also increased, when the reach 70, when the game to an end. Rules: only point in a button threading, and only in the horizontal direction or vertical direction of threading. Line to cross, but the point can not be cross-connect button. Tip: To the extent possible, to connect the connection on a long and a few more buttons.

This program segments and extracts objects from an image