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zcggzc
用递归算法对输入的任意两个字符串求最长公共子串及其出现次数(Recursive algorithm to seek the input any two strings and the longest common substring occurrences)
- 2009-11-28 13:14:39下载
- 积分:1
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TC35I-report-of-design
广东省2008年电子设计大赛本组设计报告(Electronic Design Contest, Guangdong Province in 2008 this group report)
- 2012-04-17 14:17:01下载
- 积分:1
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SCOMM
改进后的龚建伟串口调试助手V2.3.exe 的VC++6.0工程源程序(Gong Jianwei serial improved debugging the assistant V2.3.exe VC++ 6.0 project source)
- 2012-04-29 15:34:19下载
- 积分:1
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ipiqxiebo
这是一个电力系统谐波检测的MATLAB仿真模型,采用的是基于瞬时无功功率理论的ip-iq法,效果很好(This is a power system harmonic detection MATLAB simulation model, based on the instantaneous reactive power theory ip-iq method, the effect is very good)
- 2017-04-02 11:42:44下载
- 积分:1
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VCExample
基于固高GT400运动控制卡,Visual C++下的基本控制程序
(The basic control program based on Googol GT400 motion control card, the Visual C++)
- 2020-09-10 04:58:02下载
- 积分:1
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LFR
Source code for line followe Robot... aslo going to upload Schametic
- 2009-05-15 04:23:09下载
- 积分:1
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遥控器切换开关
用于多遥控器切换,能够代替教练线。
- 2022-01-22 03:43:26下载
- 积分:1
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希网动态域名不支持安装为系统服务。
就用C#写了一个。
下载此源码,请来email 告知...
希网动态域名不支持安装为系统服务。
就用C#写了一个。
下载此源码,请来email 告知-Greek does not support dynamic domain name system services to install. Used C# Write one. Download this source, please email to inform
- 2022-10-20 10:25:04下载
- 积分:1
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82790
8279 的应用。 键盘和数码管显示。
有仿真和keil 的 ASM 源码。(8279 application. Keyboard and digital display. A simulation and keil the ASM source code.)
- 2021-04-15 18:28:54下载
- 积分:1
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stm32飞控
很不错的飞控
float q0 = 1, q1 = 0, q2 = 0, q3 = 0; // quaternion elements representing the estimated orientation
float exInt = 0, eyInt = 0, ezInt = 0; // scaled integral error
void IMUupdate(T_int16_xyz *gyr, T_int16_xyz *acc, T_float_angle *angle)
{
float ax = acc->X,ay = acc->Y,az = acc->Z;
float gx = gyr->X,gy = gyr->Y,gz = gyr->Z;
float norm;
// float hx, hy, hz, bx, bz;
float vx, vy, vz;// wx, wy, wz;
float ex, ey, ez;
// ???????????
float q0q0 = q0*q0;
float q0q1 = q0*q1;
float q0q2 = q0*q2;
// float q0q3 = q0*q3;
float q1q1 = q1*q1;
// float q1q2 = q1*q2;
float q1q3 = q1*q3;
float q2q2 = q2*q2;
float q2q3 = q2*q3;
float q3q3 = q3*q3;
if(ax*ay*az==0)
- 2022-02-28 17:16:50下载
- 积分:1