在DOS下编程因为实模式的限制

Windows 2000系统编程――进程的创建-Programming Windows 2000 system-- the creation process

坐标系统与地图投影-coordinate systems and map projection

Visual C++6.0开发灰度位图处理-Visual C 6.0 grayscale bitmap processing

耳朵 检测, 适当 创建的步骤 边缘 检测 这种模式, 很多的改进 可以作 但这是 最好的解决办法 此数据库.

一本不错的好书值得看-a good look at the books worth

MFC开发ActiveX控件全过程，新手学习哦-MFC Activex

Struts开发实例.-Struts development examples.

关于JAVA中参数传递问题的总结.就这样了，想不出别的了，为什么要些那么多呢？-Parameter on the JAVA in summing up the problem. In this way, and can not think of anything else, why do so many more?

文曲星里的小游戏，本人用C语言将其编出并添加破纪录功能。游戏规则：随机产生4个数字，由玩家输入4个不重复的数字（如：8 3 1 2）按回车后电脑给出提示，其形式为"?A?B".你所输入的四位数中，位置和数字都正确则为A，数字相同但位置不相同时为B，你只可以猜10次，若你所用的次数小于纪录保持者，则为破纪录。小作一篇，请多请教！-文曲星small game, I used C language to prepare and add a record feature. The rules of the game: randomly generated four figures, by the four players enter the number of non-repetition (such as: 8 3 1 2) after the computer and press the Enter tips given in the form of ? A? B . You enter the four- the median, the location and numbers are correct, compared with A, but the location is not the same as the same as B, and you can only guess 10 times, if you used the number is less than record holder, was a record. For a small, please ask!

一个mpeg2规范文档-A mpeg2 specification documents