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On Java encryption technology and the integration of Windows
论Java加密技术与Windows的结合-On Java encryption technology and the integration of Windows
- 2022-01-26 14:17:56下载
- 积分:1
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对于这个问题的实现、刚刚给过一个程序,突然想起另外一种简单一些的方法,一并给出[笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信G...
对于这个问题的实现、刚刚给过一个程序,突然想起另外一种简单一些的方法,一并给出[笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中,我们进行语音或者业务信道解调时,都会遇到CRC的求解。通常在硬件DSP实现时,特别是40位CRC求解时候,由于生成多项式有41项,DSP最大一次能处理40位,所以使用单个寄存器会遇到一些困难,那么以下这个程序将会解决这一困难(这是针对定点DSP、C55xx的编程实现方法)。]:
-For the realization of this issue, just to have a program, suddenly reminded of another simpler way to be given [the author has long been engaged in mobile communication system modulation and demodulation of wireless links, the physical layer to achieve work. GSM in the mobile communications system, we have a voice or channel demodulation operations, it will encounter the solution of CRC. DSP hardware usually realize, especially when solving the 40 CRC, as the generation polynomial has 41, DSP can handle the largest 40, so using a single register may encounter some difficulties, then following this process will solve this One difficulty (which is for fixed-point DSP, C55xx realize programming methods). ]:
- 2022-03-14 13:54:53下载
- 积分:1
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设f(x)= 1×X2 X5 X27,分别尝试写下面的移位寄存器…
设f(x)=1+x+x2+x5+x27,试分别写出实现下列移位寄存器的程序:
以f(x)为联接多项式的DSR;
以f(x)为联接多项式的LFSR。
可供选择的联接多项式:
f1(x)=1+x+x4+x6+x30;
f2(x)=1+ x3+ x31;
f3(x)=1+ x6+ x31;
f4(x)=1+ x7+ x31;
f5(x)=1+ x13+ x31;
-Let f (x) = 1 x x2 x5 x27, respectively try to write the following Shift Register : f (x) connected to the DSR polynomial; f (x) for connectivity polynomial LFSR. Connection options polynomial : f (x) = 1 x x4 x6 x30; F2 (x) = 1 x3 x31; f3 (x) = 1 x6 x31; f4 (x) = 1 x11 x31; f5 (x) = 1 x13 x31;
- 2022-04-07 10:24:13下载
- 积分:1
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椭圆曲线Elliptic Curve)加密算法(
椭圆曲线Elliptic Curve)加密算法(-Elliptic Curve Elliptic Curve) encryption algorithm (
- 2023-04-18 23:25:03下载
- 积分:1
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OPT一次性动态口令验证算法。根据动态支持TOTP和HOTP验证。
OPT一次性动态口令验证算法。根据动态支持TOTP和HOTP验证。-A one-time dynamic password authentication algorithm OPT. According to dynamic support for TOTP and HOTP authentication.
- 2022-09-14 03:40:03下载
- 积分:1
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用C++实现的维吉尼亚密码源程序,已经在DevC++上测试过,大家可以再进行功能完善...
用C++实现的维吉尼亚密码源程序,已经在DevC++上测试过,大家可以再进行功能完善-With C++ Achievable Virginia password source, has been DevC++ Tested, we can further improve the function
- 2022-02-05 00:37:03下载
- 积分:1
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讨论了结直肠癌的一代数学算法
讨论了CRC生成的数学算法
- 2022-04-24 05:21:08下载
- 积分:1
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产生共享软件加密序列号的程序
产生共享软件加密序列号的程序- Has the shareware encryption sequence number procedure
- 2022-08-24 22:44:43下载
- 积分:1
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a generation of news summary of the procedures can be used to verify the source...
一个java语言下的生成消息摘要的程序,可用于验证来源和确定身份-a generation of news summary of the procedures can be used to verify the source and identification
- 2022-08-10 12:54:40下载
- 积分:1
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著名的解Unix密码的源程序
著名的解Unix密码的源程序 -The source for cracking unix password
- 2022-08-09 18:11:09下载
- 积分:1