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Josephu问题,一元多项式的相加问题,模拟停车场管理问题等问题...
Josephu问题,一元多项式的相加问题,模拟停车场管理问题等问题-Josephu problem, a polynomial of the sum of the problem, simulated car park management and other problems
- 2022-02-02 12:00:01下载
- 积分:1
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p2pdbanywhere 可以通过之udp方式远程连接数据库的组件,这个组件非常好,是Delphi7,9,2006能够使用,包含源码....
p2pdbanywhere 可以通过之udp方式远程连接数据库的组件,这个组件非常好,是Delphi7,9,2006能够使用,包含源码.-p2pdbanywhere adoption udp can approach the remote database connectivity components, this component was very good Delphi7, 9,2006 to use, contains source.
- 2022-02-13 03:40:50下载
- 积分:1
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求两个字符串的最长公共子序列,使用递归算法实现。
求两个字符串的最长公共子序列,使用递归算法实现。-For two of the longest common sub-string sequences, using the recursive algorithm.
- 2022-09-05 10:30:02下载
- 积分:1
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经典c程序100
每个都可以运行
内有目录
经典c程序100
每个都可以运行
内有目录-Classic c program 100 can run each of directories within the
- 2023-04-08 22:10:04下载
- 积分:1
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这个课程项目完成了给定DAG graph,找到所有拓扑排序并且输出。用到了指针和链表。对于学习C/C++和数据结构比较有帮助。...
这个课程项目完成了给定DAG graph,找到所有拓扑排序并且输出。用到了指针和链表。对于学习C/C++和数据结构比较有帮助。-this course project has output all the topological sorting given the nodes and relation for the DAG graph. This is very helpful for practicing pointer/link list in C/C++ and data structure
- 2022-07-14 12:44:04下载
- 积分:1
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Computes estimates for the number of fores ts of a graph. input as a 0
Computes estimates for the number of forests of a graph, input as a 0-1 incidence matrix. Notes: Compile in C++, "g++ -o span_forest span_forest.c". The program does not demand that the matrix is symmetric with 0 diagonal, but uses only the upper triangular part. -Computes estimates for the number of fores ts of a graph. input as a 0-1 incidence matrix. Notes : Compile in C, "g-o span_forest span_forest.c." The program does not demand that the matrix is symmetric wit h 0 diagonal. but uses only the upper triangular part.
- 2022-02-05 15:36:49下载
- 积分:1
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Will excel file sales orders into the database
将excel格式的文件销售订单导入数据库中-Will excel file sales orders into the database
- 2022-01-26 00:36:55下载
- 积分:1
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一条供需线的护航程序。他们用最短的时间..
一个关于供求陪送的线路程序。里面用到了最短路径的知识,给初学者参考-one of the lines of supply and demand escort procedures. They use the shortest path of knowledge, reference to beginners
- 2022-06-25 23:31:09下载
- 积分:1
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哈弗曼编码器,含有完整源码。文件的输入与输出。
哈弗曼编码器,含有完整源码。文件的输入与输出。-Havermann encoder, includes full source code. File input and output.
- 2022-08-24 01:35:39下载
- 积分:1
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可以实现两个大整数(不限数位)相加减! 在C++中,加减法的两个数必须在系统规定内,本程序突破了这一界限!...
可以实现两个大整数(不限数位)相加减! 在C++中,加减法的两个数必须在系统规定内,本程序突破了这一界限!-can achieve two large integers (Open-digit) is modified! In C++, and subtract the number two must be within the system, the process broke the limits!
- 2022-03-25 05:48:53下载
- 积分:1