Basic program for Home automation robo in assembly language.

9932源代码，用于9932的演示程序，各位大虾请用。-9932 source code, for the 9932 demonstration program, you prawns Please.

用89c2051实现可随机编程的小巧机器人的汇编语言源程序-Can be used 89C2051 realize compact random programming of the robot assembly language source

random.zip 随机数产生器的汇编源代码 cmdsrc.zip 一个文本编辑器的汇编源代码 ourvxd.zip 一个用汇编编VxD的简单例子 foxprn.zip 一个在Fox中利用汇编语言接口程序实现打印图形的程序 amis.zip 在汇编程序中灵活运用TSRs的程序库-random.zip random number generator to compile the source code cmdsrc.zip a text editor ourvxd.zip compilation of source code used to compile a series of simple example VxD a foxprn.zip use Fox assembler language interface program print graphics procedures amis.zip in the compilation process TSRs flexibility in the use of the library

io bios ziyuan xia zai -io bios ziyuan xia zai

汇编写的windows菜单例子-Compilation of written examples of windows menu

hotkey.rar

汇编语言超浓缩教程-assembly language-enrichment Guide

一个汇编语言集成开发写平台,对初学汇编有一定的帮助,是一个压缩包,直接解压即可(不需解压密码)-a compilation of written language integrated development platform for beginners compilation is certainly helpful, is a compressed, can be extracted directly (without extracting passwords)

DEbug 关于制作瑞星杀毒软件密钥盘的源码 MOV BX,200 ;内存基址(0面) MOV DH,00 ;磁头号00 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 3 MOV BX,300 ;内存基址(1面) MOV DH,01 ;磁头号01 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 20 ;返回dos 初学汇编，请各位多多指教！-Debug on the production of Rising antivirus software key source disk MOV BX, 200 memory base address (0 face) MOV DH, 00 head No. 00 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th interruption INT 3 MOV BX, 300 memory base address (1 side) MOV DH, 01 head No. 01 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th

单源最短路径问题-single source shortest path problem