Boutique VC7.0

圣剑II游戏文档 RPC游戏制作参考资料. 内容里有详细说明.-II game files RPC game reference materials. The contents are detailed.

opencv OpenCV is cross-platform middle-to-high level API that consists of a few hundreds (>300) C functions. It does not rely on external numerical libraries, though it can make use of some of them (see below) at runtime, if they are available

温度控制系统原程序.要用Altium Designer 6.X打开-Temperature control system the original process. Use Altium Designer 6.X Open

一个简单的俄罗斯方块程序。3个难度。 操作：A，左移；D，右移；S，加速下落；W，变形；空格，暂停。-a simple Tetris procedures. Three more difficult. Operation : A, the left; D, the rig ht; S accelerate whereabouts; W, deformation; Box suspended.

VB初级练习源码适合刚学习VB的人练习-VB source code of primary practice

计算机图形学,单边裁剪算法-computer graphics, unilateral cutting algorithm

数控译码，该程序对做数控的兄弟特别有用，里面有数控G。M代码的详细译码-NC decoding, the procedure done on the brothers NC particularly useful, NC G. inside. M detailed code decoding

Joseph Ring 算法-Joseph Ring algorithm

数根 数也有根吗？有！数根就是把一个数的各个数位上的值相加，直到得到一个一位数为止。请你编写一个程序来计算任意数N（0≤N≤1000000000000）的根。 输入： 输入有多个案例。每一个案例为一行，每行只有一个整数N。当输入的N是-1时，输入结束。 输出： 每一个案例输出一行。每行只有一个数字，就是N对应的数根。 Sample input 39 -1 Sample output 3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3

小迷宫 用c语言实现 实现的原理很简单 大家自己看吧-small maze with C Language Implementation of the principle is very simple we all Look here