详细介绍kalman filter的理论知识，通过实例说明kalman filter的工作机理...

测试工具jmeter可用来进行性能测试，功能测试以及数据库访问性能测试-Jmeter testing tool can be used to conduct performance testing, functional testing and performance testing database access

闲着无聊用TC编的一个贪吃蛇的小游戏，想试试手-TC made idle bored with a game of Snake, I would like to try hand

oracle常用傻瓜问题1000问，在网上收集了在运用oracle数据库的时候所遇到的问题-oracle problem common fool 1000 question, in the online collection of oracle database in the use of a time when the problems encountered by

领域本体的概念相似度计算，对研究语义web的很有帮助-The concept of domain ontology similarity calculation, the study of the useful semantic web

一个编译器的源程序，非常有实用价值 一个编译器的源程序，非常有实用价-a compiler of the source of great practical value to a compiler source, a very practical price

简单的计算器,适合初学者-simple calculator, suitable for beginners

这题奇数是有数学方法的，可以构造出解。描述起来比较麻烦。 出一解的构造法： 首先在整个矩阵的最下面一行的中央置1， 然后向右下方向顺序填上2,3,4,5,6,7,…… 注意碰到底的时候就将数翻到上面去，碰到右边的时候就翻到左面去 比如5*5的幻方，如果1填在(5,3)处，2就应该填在（1,4）处，4就应该填在（3,1）处…… 另外，当原数的下方已经有数时，要将要填入的数填到原数正上方 仍举5*5幻方的例子，当5已填好（4，2）时，其右下方为1，不能把6填在那里，而应填在（3,2）处，即5的上方。 最后，一个特殊的点，右下角，这时也应当将新数填在右下角的上方。-odd that this a mathematical method of solution can be constructed. Description relatively trouble. From a structural solution to the law : First, the entire matrix of the bottom of his home a central, then under the direction of the right order to fill 2,3,4,5,6,7 ... to the end of the encounter will be a few turns to above, where the right time to turn left on to For example, the 5* 5 magic squares, fill in if a (5,3), the two should fill in (1,4), four should be filled in (3,1) Department ... Also, when the original number at the bottom of several that should be filled to fill several the original number is still above 5 5* For Magic Squares example, when the five have completed (4,2), for its lower right

使用C语言写的求解一道简单的逻辑推理题的例子。具体题目请看说明。-use of the C language to write a simple solution to the logical inference that example. See note specific topics.

有关取石子游戏的程序，两人轮流取石子，取得最后石子的人输。-The stones to take the game program, the two take turns to take stone and win the final stone of the people lost.

c++源代码，关于重载-on Heavy