This is a very good program, hope to be able, through your acceptance, thank you...

NT 性能统计类NT performa 　-NT Performance Statistics category NT Performa

一个简单的进程控制与监视程序，用delphi开发的，简单得不得了-a simple process control and monitoring procedures, developed with Delphi, very, very simple!

Windows NT有映射物理内存到一个Device，这个源码告诉你怎么去访问物理内存。-Windows NT are mapping physical memory to a Device, the source tell you how to access physical memory.

VC++超简单员工考勤系统，ACCESS数据库，可以分超级管理员和一般员工用户登录，超级管理员可以维护员工信息和进行系统设置，一般员工只能考勤签到，不能进行别的操作，因此说这个考勤系统非常简单，功能很单一.-VC++ super-simple employee time and attendance system, ACCESS database, can be super-administrator and the general staff of the user log, the super administrator can carry out the maintenance of staff information and system settings, the general staff attendance attendance only, not to carry out other operations, so that The attendance system is very simple, is a single function.

取网卡号的源程序.-admission card, of the source.

安装程序制作源码-installation procedure produced FOSS

课程设计，vc++做的，基本上满足要求，只是页面总数跟随机页面号的范围一样，有待改进；答辩的时候居然问我几个系统函数有什么用，我都郁闷了，分数还没那些抄别人的高。。。。。。虽然作的不好，但怎么说也是我自己做的，无语了。放上来，有需要的拿去改改 基本上都是边查资料边写的，算得上是第一次写，错误是难免的，请大家指教，而且里面变量定义比较乱，懒得改了-curriculum design, vc do basically meet the requirements, but the total number of pages with random pages, the scope of the same, there is room for improvement; Even reply when I asked several functions What is the use, I have feelings, not those who score high copied others. . . . . . While for the poor, but that is how I do for myself, the silent. Fangshanglai there is a need to change the line of change are basically examined data writing at the same time, he can claim to be the first to write, and his mistakes are inevitable, please enlighten, but inside variables are defined more chaos, and too lazy to change the

硬盘序列号，采用VC编程-drive sequence, using VC

在ＶＣ下实现了DOS命令的重定向，输入DOS命令，或者文件的编译命令，可以在VIEW试图下显示结果，基本上可以替代CMD命令窗口-VC achieved in order to redirect DOS, enter the DOS command, or file the compiler command, you can attempt to display the results of VIEW, basically an alternative to CMD command window

求解迷宫问题，输入一个迷宫矩阵，矩阵只有1和0，1表示通行，0表示不行。是同过递归求解-Maze solving the problem, enter a maze matrix, matrix, said the passage of only one, and 0,1, 0 not do that. Been solved with the recursive