Excel文件读取

汽车租赁管理系统 随着汽车工业的发展和汽车的普及，汽车租赁成为近年来兴起的一个新兴行业。使用汽车租赁管理系统可以规范企业的管理和经营行为，减少企业的经营成本，提高工作效率。 后台数据库使用SQL Server，前台开发工具使用Visual Basic。术，并将每个数据库表的字段和操作封装到类中，从而成功地将面向对象的程序设计思想应用到数据库应用程序设计中。这也是本系统的特色和优势-car rental management system with the development of the auto industry and the popularity of car, car leasing has become in recent years the rise of a new industry. The use of car rental management system can standardize the management of enterprises and the business behavior and reduce the operating costs of enterprises, improve work efficiency. Background database using SQL Server, future development tools to use Visual Basic. Operation and each database table fields and operation of the Packaging category, thus the success of object-oriented programming design concepts applied to the database application design. This is also the system"s characteristics and advantages,

显示TCP连接表， 显示TCP连接表， 显示TCP连接表， 显示TCP连接表， -tcpdhasdpasdasdsadasd sadsa dsad sad as

Portable thread-based garbage collection library, for C-LibGC is a thread-based garbage-collection library with the following features: thread-based garbage collection. precise collection. uses the mark & sweep algorithm. portable uses no low-level O/S-specific features. no dependencies headers only. weak pointers. garbage-collected strong and weak arrays. customizable garbage collection with user-defined finalize and mark callbacks. wrapper class for non-garbage-collected classes.

队列实现的函数算法！-queue algorithm to achieve the function!

安装程序制作源码-installation procedure produced FOSS

Visual C＋＋环境下，获取主机名及IP地址，从中可以了解VC环境下硬件编程的知识。-Visual C++ environment, access to the host name and IP address, One can understand the VC environment hardware programming knowledge.

C#API大全 内置大量的在C#中申明的API函数接口，方便大家在C#中使用API函数

这是易语言的系统清除垃圾源码，原理很简单，产生批处理来删除垃圾。-language that is easy to remove the garbage source system, the principle is very simple, to have a batch delete garbage.

自动重启、注销、关机等-automatic restart, canceled, shutdown

求解迷宫问题，输入一个迷宫矩阵，矩阵只有1和0，1表示通行，0表示不行。是同过递归求解-Maze solving the problem, enter a maze matrix, matrix, said the passage of only one, and 0,1, 0 not do that. Been solved with the recursive