C # lineage2芙蕾雅PTS源

这个程序是用java写的一个模拟进程各种状态之间的转换。通过不同的操作，直观的看到进程之间的状态转换是由什么操作引起的。-the procedure is written in java with a variety of modeling process for conversion between the state. Through the operation, intuitive process to see the state of transformation is what caused the operation.

.写一个程序，能够读一行 string, 然后打出 最长的 那个 substring p （就是最长的小分句），并且那个小分句要求出现超过一次的。如果有超过1个那样的substring, 只要打出那个字母顺序排后面的-. To write a program that can read his string, and then played the longest substring p (is the longest small clause), and request that a small clause appears more than once. If there is more than one kind of substring, as long as the shot was behind schedule in alphabetical order

关于C的小程序。，希望大家有需要，看看总没坏处的-on small procedures. Hope you need to see the total not harm.

License Options file and may replace Named Users for a Program, whether temporarily or not, no more than four (4) times per year, prov file never exceeds the number licensed per Program. Portions of the Programs may be installed on individual computers to accelerate startup times, as long as the-License Options file and may replace Named Users for a Program. whether temporarily or not. no more than four (4) times per year. 577 file never exceeds the number licensed per Program. Portions of the Programs may be instal led on individual computers to accelerate star tup times, as long as the

AsynchIO shows how to use OPC events synchronously

正则表达式,不错的好东西,有需要了解和学习的下载不吃亏-Regular expressions, good good things, there is a need to understand and learn the download does not suffer

题目：某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下： 　　　每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。 -Topic: using a public telephone transmission of data, integer data is four, in the transmission process is encrypted, encryption rules are as follows: each number plus 5, and then use and the balance divided by 10 instead of the figures, then the first and fourth exchange, second and third exchange.

Lex和Yacc分析器的程序-Lex and Yacc analyzer procedures

房间开始的使得开房间是得分看见似的放开了间的释放看的释放空间似的放了看见的释放较快-Makes the rooms began to open to see if the room is open the scoring between the release of the release to see if put in space to see the release of a faster

获取鼠标在任意点上的位置-access to any point in the mouse position on the