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C源码生成一个自己的口令字典
C源码生成一个自己的口令字典-C source code generated a dictionary of their own passwords
- 2022-03-30 05:25:26下载
- 积分:1
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28sf040a
28sf040a
- 2022-07-24 06:21:27下载
- 积分:1
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shell教学视频,非常适合初学者。希望通过审核!
shell教学视频,非常适合初学者。希望通过审核!-shell teaching video, very suitable for beginners. Hope that through review!
- 2023-05-31 02:00:04下载
- 积分:1
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这是模式识别中关于k均值动态聚类算法的matlab源码
这是模式识别中关于k均值动态聚类算法的matlab源码-This is the pattern recognition on the k-means clustering algorithm Matlab FOSS
- 2022-05-26 09:58:54下载
- 积分:1
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thinkinc++(书,中文,源码),初学者必备的一本好书
thinkinc++(书,中文,源码),初学者必备的一本好书-thinkinc++ (books, Chinese, source), beginners must have a good book
- 2022-04-16 18:11:26下载
- 积分:1
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玩双色球的过程中,无论把33个红色备选号码球怎样划分区间,总会时不时地有某个区间不出号(即所谓的断号或断档)。如果我们在选号时,能够把不出号的区间排除在我们选号...
玩双色球的过程中,无论把33个红色备选号码球怎样划分区间,总会时不时地有某个区间不出号(即所谓的断号或断档)。如果我们在选号时,能够把不出号的区间排除在我们选号范围之外,就会大大缩小选号的范围,增加中奖的机会。
-Loans play the process, regardless of the number 33 red balls what division options range from time to time there will always see a certain number range (the so-called off or断档).选号If we can not issue the interval excluded from the scope of our选号, it will greatly narrow the scope of选号to increase the chance of winning.
- 2023-04-30 03:50:04下载
- 积分:1
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汇编程序从键盘输入一个字符,要求调用bios中断,并用八进制的形式显示其扫描码和ascii码...
汇编程序从键盘输入一个字符,要求调用bios中断,并用八进制的形式显示其扫描码和ascii码-assembler input from the keyboard of a character, called bios interrupt request, and octal form indicating their scan code and code ascii
- 2022-05-23 23:00:59下载
- 积分:1
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能在MDT5/6环境下对已经存在地曲面进行全部和局部区域展开,同时能进行源曲面和展开平面上点和线地相互映射...
能在MDT5/6环境下对已经存在地曲面进行全部和局部区域展开,同时能进行源曲面和展开平面上点和线地相互映射-in MDT5/6 right environment to surface already exists for all regional and local begin and can be the source for surface and start Plane dots and lines to the mutual mapping
- 2022-01-31 19:42:12下载
- 积分:1
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一个关于LabVIEW的pwm程序,还没有最终完成
一个关于LabVIEW的pwm程序,还没有最终完成-pwm
- 2022-01-26 00:20:57下载
- 积分:1
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Interval coverage of the realization of the algorithm description: In this paper...
区间覆盖问题的算法实现
问题描述:给出x轴上N条线段的坐标,从中选出一些线段来覆盖区间【0,M】,要求所用线段数目最少
-Interval coverage of the realization of the algorithm description: In this paper, x-axis N be the coordinates of line segment, selected to cover a number of line segments [interval 0, M], requirement by the number of segments at least
- 2022-12-22 05:20:03下载
- 积分:1