数据匹配，初学者必备，读取网页邮箱的代码

MICROSOFT JOURNAL 源代码集,仅仅只是为了学习和交流-MICROSOFT JOURNAL source code set, merely to learn and exchange

Control_demo

c语言词法分析，功能比较全，大家随便看看吧，有界面-The file is for accidence analysis fo C language and has lots of functions. It has the interface and please check it freely.

这个是一个小型计算器，你可以输入一个表达式，就可以得到答案，支持优先级运算，-This is a small calculator, you can enter a regular expression, we can get an answer in support of Operation priority,

资源描述windows下用curl编写的一个简单的连接httpserver的源码，使用post的方法。

C++通用算法之修正算法，其中包括查找容器中相同的元素，容器中相同的元素统计等等，这些算法都比较高效，直接就可以复制使用，特别方便。这些代码都是经过自己推敲研究过的-C generic algorithms correction algorithms, including the search for packaging the same elements, Vessel Statistics same elements, and so on, these algorithms are more efficient and can directly copy, in particular convenience. These codes are weighing himself studied the

M伪随机序列生成器算法 这个Matlab算法用于生成二元、三元及五级的，m序列。可以用于直接扩频通信等 系统中的，伪随机序列生成器。-M pseudo-random sequence generator algorithm for the Matlab algorithm is used to generate binary, ternary, and five of the, m sequence. Can be used to direct spread spectrum communication system, the pseudo-random sequence generator.

翻译 maninwest@Codeforge作者:Yvan Rodrigues@CodeProject 使用代码 using System; using System.Windows.Forms; namespace RedCell.App.Calculator.Example { public partial class Form1 : Form { private double accumulator = 0; private char lastOperation; public Form1() { InitializeComponent(); } private void Operator_Pressed(object sender, EventArgs e) { // An operator was pressed; perform the last operation and store the new operator. char operation = (sender as Button).Text[0];

FIR串并架构，可以看看哦！很有用处的！-FIR string and structure that can take a look at Oh! Useful!

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected