rs232.cpp和RS232串行端口通信。H

AVR单片机串口异步通信,通过电脑串口助手使电脑和单片机运行简单的数据通讯-AVR microcontroller tramsmition

一个比较简单的BCB串口源代码，稍微加以改变就可以进行串口的应用了-a relatively simple serial BCB source, a little change can be for the use of Serial

串口的监控程序,提供了固定命令模式和，用户自定义模式。-serial monitoring procedures, and providing a fixed command pattern and user-defined mode.

openrisc mini_or1200, 包括 or1200、uart16550、dbg_interface、mem_if(片上内存)这几部分。-openrisc mini_or1200, including or1200, uart16550, dbg_interface, mem_if (memory chip) in these parts.

具有高可靠性的高速连续数据采集的设计与实施方法，一篇有关数据采集的论文-highly reliable high-speed data acquisition for the design and implementation methods, a data acquisition papers

实际是一个网络编程中模拟读写串口的程序.不过是创建了一个文件,把文件当作串口进行操作-is actually a simulation of network programming literacy Serial procedures. But is the creation of a paper document to operate as a serial

vc,串口通讯类和用这个类编写的一个例子程序-vc, serial communications and the use of this type of an example of the preparation process

可以控制串口RTS DTR引脚电压分布的小程序

SZ328串行通讯驱动及应用开发包,为2个CPU间协议通讯应用实例.-SZ328 serial communication driver and application development kit for the two inter-CPU communication protocol application.

这是非常有挑战性的题目。对于用户输入的任意一个平面函数f(x)，绘制出其函数曲线。这里最关键的技术难点就是如何实现计算表达式的值。在《编译原理》和《数据结构》的书中，都有对表达式运算方法的论述。说实在的，在编译型计算机语言中实现对用户输入表达式的运算是非常困难的。需要对表达式进行扫描，去括号，按照运算符的优先级生成2叉树，然后遍历该树生成逆波兰表达式，再然后通过栈的方法进行运算。如果在表达式中再包含有函数的话......描述起来都麻烦，更不要说用程序实现了:-(-This is a very challenging issue. For user input an arbitrary planar function f (x), mapping out its function curves. Here the most critical technical problems is how to achieve calculated the value of the expression. "Compiling Principle" and "data structure," the book, have right of expression Operational discussed. Indeed, the computer language compiler to achieve expression of the user input operation is very difficult. Need to scan expression to the brackets, in accordance with the priority Operators Generation 2-ary tree, and then traverse the tree generated reverse Polish expression, and then through the stack approach to computing. If the expression again contains the function described ...... these are trouble, not to mention t