mysql-5.0.45.tar.gz

数据结构中栈的经典算法――第一类背包问题，已经通过测试！-The stack data structure in the classic method- The first knapsack problem, has passed the test!

用VFP编的电脑查询系统,比较简单,适合初学者参考.-with VFP addendum to the computer search system, a relatively simple reference for beginners.

比较六种排序算法，其中包括快速排序，冒泡排序等内容的速度以及空间复杂度。-Comparison of the six sorting algorithms, including quicksort, bubble sort etc. the speed and space complexity.

在设计会计软件时,常常要把小写金额转换为大写金额,通过本例,你只要输入小写数字,即可转为大写金额.-accounting software in the design, it is often the amount should lowercase to uppercase conversion rates, through the cases, as long as you input lowercase figures, the amount can be converted to uppercase.

ch_lettres est une 统一德尔福倒拉转换 des chiffres en 纯文学法文

求图的任两结点间的距离，(2) 用二维数组存放C和A ，C是原成本矩阵，A 是求出的距离矩阵 (3) 算法采用三重循环，其中最外层的循环变量必须代表中间结点，中层的循环变量代表头结点而内层循环变量代表尾结点。 (4) 试着把三层循环变量的顺序作些改变，最外层的循环变量仍代表中间结点，而中层循环变量代表尾结点，内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同 (5) 显示结果要清晰易懂 (6) 本题运行结果 -Order to map any of the distance between two nodes, (2) with two-dimensional array of storage C, A, C is the original cost matrix, A is to find the distance matrix (3) The algorithm uses the triple loop, one of the most outer loop variable must be representative of intermediate nodes, the middle loop variable represents the first node and the inner loop variable represents the end nodes. (4) tried to three-loop order of the variables to make some changes, the most outer loop variables still represent intermediate nodes, while the middle loop variable represents the end nodes, the inner loop variable represents the first node. The two approaches to compare the results to see whether the results the same (5) shows the results must be clear and understandable (6) The q

想学习算法的朋友，可以看看拉格朗日算法参考参考-Want to learn algorithms Friend, you can look at the Lagrangian algorithm reference reference

图的常用算法，比较全面 并有一种求图的最短路径的算法， 欢迎指正，-map commonly used algorithms, a more comprehensive and a map for the shortest path algorithm welcome correction, thank you

集装箱的装箱问题 给定一个集装箱，其长为L，宽为W和高为H，现有一批圆柱形木材，每根木材的长均为L，但是半径不同，设第i根木材半径为ri。问如何装箱，使得集装箱的空间利用率最高？-problem given a container, its length L, width W and H for high, existing batch of cylindrical wood and each timber are long L, but different radius, based i-radius of the wood-ri. Asked how crates, containers make maximum utilization of space?

此为初步实现，简单直观，可在此基础上增强功能。-preliminary achieve this, simple, and the basis of this enhanced functionality.