用vc和cj60lib做的读取shape文件的源代码.还有些小问题没做完。...

当司机在一个地方没有油时，它应该在去那个地方去加油，走那条路为够更好的为他（她）服务，这条路又会经过那些地方， 系统会生成一个解决方案为司机提供一个选择的机会。-when the driver in a place without oil, it should go to those places to refuel and which way to go to better enough for him (her), this road will go through, system will generate a solution for the drivers an opportunity to choose.

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在DOS下用Port IO的方式取得PCI总线的信息-DOS with the Port IO PCI obtained the information

一套不错的房产，大家可以用用，非常不错哈-a good property, we can use. Very good Kazakhstan

医院门诊管理系统，根据管理员的登录，可以进行医院门诊的管理，对病人进行住院和医用的记录-Hospital out-patient management system, according to the registry administrator, you can out-patient hospital management, hospital patients and medical records

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DOS完整源码。都是微软高手写的，能不经典吗？ 看完肯定有提高。-DOS full source code. Are written in Microsoft" s master, can not classical texts? Reading certainly increase.

一个简单的JAVA小旅馆的程序，功能简单，课程设计的作业-a simple Java small hotel procedures, functions simple, curriculum design operations

现在广被认可的ｎｃｉｅ考试的有关试题！ 有兴趣的可以看看！-now widely recognized ncie examination of the papers! Interested parties can see!

问题描述: 一杯沸水冷却，圆柱体模型，底面半径0.05m，高0.1m，周围温度20度，初始水温100度 方程是四维输运方程（常数a^2=k/(c*p)，k是热传导系数0.6006焦/（米*秒*度）） 初始条件：t=0时水等于100度 边界条件：1.上下壁都是自由冷却，第三类边界条件，周围温度保持在20度（H=k/h,h取1） 2.杯壁绝热，第二类边界条件 图形显示格式,取过圆柱轴的截面温度变化将其做成动画. -Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.