思科路由ebootk，这是PDF文件，你必须使用Adobe 8…

传教士与野人问题我们分两种情况考虑。先考虑船在左岸的情况。如果不考虑限制条件，也就是说，船一次可以将三人从左岸运到右岸，然后再有一个人将船送回来。这样，船一个来回可以运过河2人，而船仍然在左岸。而最后剩下的三个人，则可以一次将他们全部从左岸运到右岸。所以，在不考虑限制条件的情况下，也至少需要摆渡[(M+N-3)/2]*2+1次。其中分子上的"－3"表示剩下三个留待最后一次运过去。除以"2"是因为一个来回可以运过去2人，需要[(M+N-3)/2]个来回，而"来回"数不能是小数，需要向上取整，这个用符号[ ]表示。而乘以"2"是因为一个来回相当于两次摆渡，所以要乘以2。而最后的"＋1"，则表示将剩下的3个运过去，需要一次摆渡。-M-C products

visual c++编程的电子教案,学习资料-visual electronic lesson plans, learning materials

this is a introduction book about genetic algorithm

msp430x14x程序，是子程序，用于调试-msp430x14x process, the subroutine for debugging

Autonomous indoor mobile robots are gaining increasing popularity for the shared use in military and civil applications. Recently aerial or ground robots of various shapes and sizes have been developed for quick detection and observation of circumstances in calamity environments such as indoor fire spots [1, 2]. In an indoor environment, however, weak reception of GPS signals has posed additional challenges to the operation of the robots. Therefore less expensive self-localization with unaided external sensors is one of the most important problems in popularizing indoor mobile robot products.

有关计算机硬软件知识的英文教材-on computer hardware and software knowledge of English teaching

傲慢与偏见 不错的经典-Pride and Prejudice good classic

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这是关于两种环境下,VC++和TurboC中关于串口通信的编程资料.希望能帮助大家-which is about two circumstances, VC and Turbo on serial communication programming information. we hope to help

tapestry开发过程中的一些常用组件以及参数的介绍-tapestry development process a number of commonly used components, as well as introduce parameters