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编程
简单的绘图小游戏
可供初学者参考使用
编程
简单的绘图小游戏
可供初学者参考使用-programming simple little game of drawing reference for beginners
- 2023-01-05 20:25:03下载
- 积分:1
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clear all clc
load C:a_RADARSAT_ProcessingRead_the_CDEXTRACTED_DATACDdata1...
clear all clc
load C:a_RADARSAT_ProcessingRead_the_CDEXTRACTED_DATACDdata1
sig=double(data) [M,N]=size(sig)
sig_fft=fft(sig) clear sig data -clear all clc
load C:a_RADARSAT_ProcessingRead_the_CDEXTRACTED_DATACDdata1
sig=double(data) [M,N]=size(sig)
sig_fft=fft(sig) clear sig data
- 2022-10-23 08:30:04下载
- 积分:1
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浙江大学编程竞赛语言组做的
浙江大学程序设计竞赛c语言组二等奖做平,五子棋,有原马和报告文档,共参阅-Zhejiang University Programming Contest c language group to do- the second prize, 331, the original Ma and report files, a total of reference
- 2022-08-25 16:13:25下载
- 积分:1
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由VC实现的对不同裁剪面的茶壶的绘制,对初学者很有帮助
由VC实现的对不同裁剪面的茶壶的绘制,对初学者很有帮助-by VC on the different cutting surface mapping of the teapot, very useful for beginners
- 2022-08-03 20:33:28下载
- 积分:1
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pixel mapping with Win32SDK prepared for a bitmap
象素绘制 用Win32SDK编写的一个bitmap库-pixel mapping with Win32SDK prepared for a bitmap
- 2022-01-26 04:32:17下载
- 积分:1
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bmp图片的三维重构和三方向视图的显示,用delphi开发
bmp图片的三维重构和三方向视图的显示,用delphi开发-bmp images and the three-dimensional reconstruction of three directions View shown that the development of delphi
- 2022-11-24 18:35:03下载
- 积分:1
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一个实现浏览BMP图像的例子,是从网上down下来的,不知道这里有否,如无,算是成功了...
一个实现浏览BMP图像的例子,是从网上down下来的,不知道这里有否,如无,算是成功了-a surfing BMP image examples, down from the Internet down, I do not know whether it here, if not, as a success
- 2023-04-19 13:45:02下载
- 积分:1
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一个动态墙纸更换的程序,可以按自己的需求,定时的更换墙纸
一个动态墙纸更换的程序,可以按自己的需求,定时的更换墙纸-a dynamic wallpaper replacement procedures, in accordance with their needs, regular replacement of wallpaper
- 2022-11-03 10:05:03下载
- 积分:1
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Hough变换用来在图象中查找直线。它的原理是:假设有一条与原点距离为s,方向角为θ的一条直线,直线上的每一点都满足方程 s=x*Cosθ+y*Sinθ,利用这...
Hough变换用来在图象中查找直线。它的原理是:假设有一条与原点距离为s,方向角为θ的一条直线,直线上的每一点都满足方程 s=x*Cosθ+y*Sinθ,利用这个事实,我们可以找出某条直线来。这段程序,用来找出图象中最长的直线。-Hough Transformation is used for searching lines in an image . Here is the principle:
Assume there is a line whoes direction is "sita" , and the distance from the origin to this line is s. So each point in this line satisfies the equation : s=x*Cos(sita)+ y*Sin(sita) . We can find out the lines based on this fact.
And this programme is to find out the longest line in the image.
- 2022-09-05 00:30:03下载
- 积分:1
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main five
主要实现五角星图形的绘制,希望能提供参考作用-main five-pointed star graphics rendering, hope to provide useful reference
- 2022-06-18 03:13:52下载
- 积分:1