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DSP与电脑的网络连接程序 1
DSP与电脑的网络连接程序 1
- 2023-02-02 22:05:03下载
- 积分:1
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vb中一些常见问题的讲解及帮忙,对初学者很有帮助
vb中一些常见问题的讲解及帮忙,对初学者很有帮助-vb some common problems on and help helpful for beginners
- 2022-11-14 12:50:03下载
- 积分:1
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这个论坛也不错.适合做毕业设计的,包含大多数基本功能
这个论坛也不错.适合做毕业设计的,包含大多数基本功能-this forum is a good one. Suitable for graduation design, including most of the basic functions
- 2022-06-21 02:47:19下载
- 积分:1
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通过鼠标可以控制图片的缩放功能,我把该功能模块封装成用户自定义控件了,希望对大家能够有用!...
通过鼠标可以控制图片的缩放功能,我把该功能模块封装成用户自定义控件了,希望对大家能够有用!-Mouse can be controlled through a zoom feature picture, I package the functional modules into a custom control users, and hope we can be useful!
- 2022-09-21 15:30:04下载
- 积分:1
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Treatment of data, and research and development for specific projects, based on...
对数据的处理,和对具体项目的研发,基于C语言的策划和程序设计-Treatment of data, and research and development for specific projects, based on the C language, planning and program design
- 2022-05-30 23:39:13下载
- 积分:1
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介绍WCF的基础知识,非常适合初学者学习的源代码。
介绍WCF的基础知识,非常适合初学者学习的源代码。-Introduce the basics of WCF is very suitable for beginners to learn the source code.
- 2022-08-25 14:10:13下载
- 积分:1
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基本操作的基本操作是四大操作,符号…
浮点数基本运算 浮点数的基本运算主要有四则运算、符号处理、大小比较,以及浮点数分柝等。 包含头文件 "fn.hpp" #include "fn.hpp" 浮点数基本运算 浮点数的基本运算中有加、减、乘、除、取负、绝对值、相等比较等。 加减乘除 加、减、乘、除四个运算极为相似,都是需要两个参数,结果当然也是浮点数了。 例子: // 加 减 乘 除 btil::fn::plus::value // f1+f2 的结果 btil::fn::minus::value // f1-f2 的结果 btil::fn::multiplies::value // f1*f2 的结果 btil::fn::divides::value // f1/f2 的结果 plus::value::f_val // f1+f2 的结果的值 struct one { static const double f_val = 1.0 } // 两个浮点数 struct two { static const double f_val = 2.0 } minus::value::f_val == 0.5 取负 取负运算就是取一个浮点数的负数。-float basic operations of the basic operations are four major operations, symbols, sizes, and float-watchman"s rattle so. The first document contains "fn.hpp"# include "fn.hpp" float float basic operations of the basic operations are, plus or minus, riding, except from negative, in absolute terms, a comparison of the same. The a
- 2022-05-22 17:45:03下载
- 积分:1
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课程设计,希望对大家有一定的参考价值,谢谢大家
课程设计,希望对大家有一点参考价值,-curriculum design, we hope to have some reference value, thank you
- 2022-02-26 08:07:56下载
- 积分:1
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问题描述:
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*...
问题描述:
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*p),k是热传导系数0.6006焦/(米*秒*度))
初始条件:t=0时水等于100度
边界条件:1.上下壁都是自由冷却,第三类边界条件,周围温度保持在20度(H=k/h,h取1)
2.杯壁绝热,第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
-Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.
- 2022-05-12 17:55:03下载
- 积分:1
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摘得 有序样品聚类
摘得 有序样品聚类-Won orderly clustering method
- 2022-02-05 13:33:17下载
- 积分:1