图像的处理方面的,还请大家指教.谢谢. 怎么传不上呢

在.net环境下开发的通过读取DWG的头文件，预览DWG中的图形-In. Net development environment by reading the header files DWG, DWG to preview the graphics

好好的师傅说的好防守进攻防守的话部分是大方说的功夫还是打狗棒法都是官方的师傅给多少-good

svga编程,-svga programming ,

此源代码将演示如何用C,Win 32 SDK及GDI+来实现边缘检测。(C++,C)-this source code to demonstrate how to use C, Win 32 SDK GDI and edge detection to achieve. (C, C)

是关于梯度矢量流snake的程序代码，长须很详细，可以学到梯度矢量流snake模型中能量函数的计算方法。-Gradient vector flow snake on the program code, long to be very detailed and can learn a gradient vector flow snake model in the energy function is calculated.

一个2dimension直方图的算法包括相应的程序。-A histogram 2dimension algorithms, including the corresponding procedures.

Visual C# 2005 编写的很精致实用的电子钟-Visual C# 2005 was exquisitely prepared by the practical electronic bell

用C实现的多边形填充算法,该算法效率很高,经过实际应用-C realized polygon filling algorithm, which is highly effective, practical applications after

详细用法请看文件说明，该程序用matlab编写，挂用vc＋＋编译器编译而成，程序用途：找出在任意多变形内的象素点-detailed document indicates that the procedures used to prepare Matlab, linked with vc++ compiler compiler which, procedures purposes : to identify more arbitrary deformation within the pixel point

直线扫描算法rivate AX1(100) As Integer, AY1(100) As Integer, AX2(100) As Integer, AY2(100) As IntegerPrivate CX1 As Integer, CY1 As Integer, CX2 As Integer, CY2 As Integer, N As IntegerPrivate Sub form_Load()Picture1.BackColor = RGB(255, 255, 255)N = 0End SubPrivate Sub picture1_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)If Button = 1 ThenCX1 = CInt(X): CX2 = CInt(X)CY1 = CInt(Y): CY2 = CInt(Y)End IfEnd Sub-linear scanning algorithm rivate AM1 (100) As Integer, AY1 (100) As Integer, AX2 (100) As Integer, AY2 (100) As IntegerPrivate CX1 As Integer, CY1 As Integer, CX2 As Integer, CY2 As Integer, N As IntegerPrivate Sub form_Load () Picture1.BackColor = RGB (255, 255, 255) N = 0End SubPrivate Sub picture1_MouseDown (Button As Integer, Shift As Integer, As Single X, Y As Single) If Button = = a ThenCX1 CInt (X) : CX2 = CInt (X) = CY1 CInt (Y) : CY2 = CInt (Y) End Sub IfEnd