最小二乘法多次曲线拟合算法

这是一个jsp开发的CMS(网站内容发布)系统源码，非常值得看。-This is a CMS(content management system) developed with jsp, it is worth to learn.

STR7系列32位ARM控制器的固件库，使开发此类控制器变得简单容易，内含AD，CAN，USRT，EMI等共14个例程。-STR7 family of 32-bit ARM controller firmware library, so that the development of such a controller has become simple and easy, including AD, CAN, USRT, EMI, such as a total of 14 routines.

基于VHDL的全数字锁相环的设计 有关键部分的源代码 hehe !-VHDL-based all-digital phase-locked loop has a key part of the design of the source code hehe!

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精彩特效之位图的飘动.rar-position wonderful effects of the plan wafted. Rar

数根 数也有根吗？有！数根就是把一个数的各个数位上的值相加，直到得到一个一位数为止。请你编写一个程序来计算任意数N（0≤N≤1000000000000）的根。 输入： 输入有多个案例。每一个案例为一行，每行只有一个整数N。当输入的N是-1时，输入结束。 输出： 每一个案例输出一行。每行只有一个数字，就是N对应的数根。 Sample input 39 -1 Sample output 3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3

这是小时候的小孩玩过的比较经典的一款小游戏贪吃蛇，适合c++初学者借鉴-This is when the kids played a comparison of the classic Snake game for c++ beginners learn

本书是为工科高年级学生写的教科书，可以作为控制系统领域的首门课程的教材。本书详尽地论述了连续控制系统的分析和研究方法，各章节包括动态系统的数学模型、瞬态响应和稳态相应分析、根轨迹分析、控制系统设计的根轨迹法、频率响应分析、控制系统设计的频率响应法，以及PID控制与二自由度控制系统等内容。-This book is for the engineering of high-grade students to write the textbooks, can serve as a control system for the field of teaching the first door. The book discusses in detail a continuous control system analysis and research methods, including dynamic system of various sections of the mathematical model, the corresponding transient response and steady-state analysis, root locus analysis, control system design of the root locus method, frequency response analysis, control System frequency response method, as well as PID control and two degrees of freedom control system, etc..

通知: 选修《信息安全》的同学请注意了,本课已停课了,不再上了,期末成绩是以交作业的形式来考核,作业有2个,少交一个将不会及格. 1.编程题: 用任何一种语言编写一个扫描器,扫描形式不限,必须能对端口进行扫描,如果觉的能力有限的同学,可以选择本书第三章,课后的任意一道编程题来做.(本题编好以后，用邮件的形式发给他,E-mail:gyx317@21cn.com,邮件的主题请写清楚学院、01级、学号、姓名-notice : elective "information security" to the students, the fugitive has been closed and will not last, the end is perpendicular operation results in the form of assessment, two operations are paid less one will not pass. 1. Programming that : any language to prepare a scanner, scanning free in style, should be able to port scan, if the limited capacity McGREGOR students will be able to choose the book III, the after-school program and that an arbitrary do. (Part of the good that the future use of the mail sent to him, E-mail : gyx317@21cn.com, Post pieces of the theme please write clearly College, 01, the school, names

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