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一个费诺编码器,输入N个总和为1的小数,就可以得到N个费诺码
一个费诺编码器,输入N个总和为1的小数,就可以得到N个费诺码-a fee Connaught encoder input N sum of a minority, it can be N Connaught yards charges
- 2022-07-11 04:35:49下载
- 积分:1
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C语言数值计算中常用的函数,如sin(x),cos(x)的实现方式的源代码。...
C语言数值计算中常用的函数,如sin(x),cos(x)的实现方式的源代码。-Codes for functions which are used frequently in numerical calculation ,such as sine function,cosine function, written in C language
- 2022-02-06 23:03:08下载
- 积分:1
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Lagrange interpolation, have done an interpolation algorithm
Lagrange插值,自己做的一个插值算法-Lagrange interpolation, have done an interpolation algorithm
- 2022-04-10 18:22:17下载
- 积分:1
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用于数学编程的基本数学类
basic mathematic classes used for math programming
- 2022-07-03 07:13:05下载
- 积分:1
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介绍了GS算法的核心内容,为想学习GS算法的人士提供很好的参考...
介绍了GS算法的核心内容,为想学习GS算法的人士提供很好的参考-Introduction of the GS algorithm is the core content for the GS algorithm to learn to provide good reference
- 2022-03-12 07:10:41下载
- 积分:1
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趣味问题的程序原代码 海滩上有一堆桃子,五只猴子来分。第一只猴子把这堆桃子凭据分为五份,多了一个,这只 猴子把多的一个扔入海中,拿走了一份。第二只猴子把剩...
趣味问题的程序原代码 海滩上有一堆桃子,五只猴子来分。第一只猴子把这堆桃子凭据分为五份,多了一个,这只 猴子把多的一个扔入海中,拿走了一份。第二只猴子把剩下的桃子又平均分成五份,又多了 一个,它同样把多的一个扔入海中,拿走了一份,第三、第四、第五只猴子都是这样做的, 问海滩上原来最少有多少个桃子?- On the interest question procedure original code beach has pile
of peaches, five monkeys divide. The first monkey divides into this
pile of peach proof five, many, this monkey has thrown into many in
the sea, took away. The second monkey the peach which is left over
equally divides into five, also many, it similarly has thrown into
many in the sea, took away, third, fourth, the fifth monkey all is
does this, asked how many peaches on the beach most is originally
unusual?
- 2022-10-26 14:25:03下载
- 积分:1
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几exapmles的马佩尔
sevral exapmles of mapel
- 2022-04-14 20:51:15下载
- 积分:1
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ICEM CFD基础教程,学习流体力学的朋友可以参考。
ICEM CFD基础教程,学习流体力学的朋友可以参考。-ICEM CFD Basic Course, learning hydromechanics friends can refer to.
- 2022-12-07 20:30:04下载
- 积分:1
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Pic 的粗糙 rx
用于伴随 keyfob 固件粗糙ChipKit 系列屏蔽 * / / * * * 注: 对使用 PIC12LF1840T48A 的引用
- 2023-03-12 06:55:03下载
- 积分:1
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偏微分方程的基于GPU的模拟器。
PDE simulator on GPU.
- 2022-10-01 16:40:03下载
- 积分:1