VC++6做的一个 开机自动运行 还不是很完善 不过例子不错

This code for find object on the map

lcd液晶12232F的串口C51程序 功能：只要用三根线就能够实现lcd的所有显示功能-LCD LCD 12232F C51 Serial procedures functions : Just three lines can be realized LCD display all

文件管理系统...由c++设计实现...编缉运行即可-file management system

javaweb 酒店管理系统 有数据库

本模块演示了如何与三轴数字加速度计 ADXL345 ac:Accel mmB STM32 M3 上进行通信。从加速度计的值显示在 TFT 显示器上。

sqlitedll的源代码，用于在程序中直接调用-sqlitedll source code, can be called directly from program.

使用Qtcreatot的KCF跟踪代码。本人测试了，是可以用的。KCF跟踪，速度很快，但是有一个缺点就是遮挡之后跟踪效果不好。

电路布线问题要确定将哪些连线安排在第一层上，使得该层上有尽可能多的连线。换句话说，该问题要求确定导线集Nets={(i,π(i)),1≤i≤n}的最大不相交子集。-circuit wiring problem will be to determine which connections in the first layer, making this layer as much as possible on the log. In other words, the problem defined Traverse Set Nets = ((i, (i)), 1 i n) is not the largest subset of the intersection.

ZThread库是一个开源的跨平台高级面向对象的线性和sycnchronization 库，以运行POSIX 和Win32 系统中的C++程序。

for： Root of a Polynomial --- --- --- --- -- Time Limit: 1 Second Memory Limit: 32768 KB -------------------------------------------------------------------------------- A polynomial of degree n has the common form as . Your task is to write a function to find a root of a given polynomial in a given interval. Format of function double Polynomial_Root(int n, double c[], double a, double b, double EPS) where int n is the degree of the polynomial double c[] is an array of n +1 coefficients , , ..., , and of the given polynomial double a and b are the two end-points of the given interval and double EPS is the accuracy of the root. The function must return the root. Note: It is guaranteed that a unique real number r exists in the given interval such that p(r) = 0. -for: Root of a Polynomial---------------------- Time Limit: 1 Second Memory Limit: 32768 KB-------------------------------------------------------------------------------- A polynomi