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SDK tools, segmentation, such as TREE Control Demonstration code
SDK 工具条,分割条,TREE 等控件演示代码-SDK tools, segmentation, such as TREE Control Demonstration code
- 2022-03-31 06:53:28下载
- 积分:1
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服从正态分布序列,一个很小的一个算法,需要具体修改才能使用...
服从正态分布序列,一个很小的一个算法,需要具体修改才能使用-Obey normal distribution sequence, an algorithm for a small, specific changes need to use
- 2023-02-16 06:10:04下载
- 积分:1
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码数字图像处理。
Codes digital image processing.
- 2022-03-26 09:13:49下载
- 积分:1
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给定的字母表A 由26 个小
写英文字母组成A={a,b,…,z}。该字母表产生的升序字符串是指字符串中字母按照从左到
右出现的次序与字母在字母表中出现...
给定的字母表A 由26 个小
写英文字母组成A={a,b,…,z}。该字母表产生的升序字符串是指字符串中字母按照从左到
右出现的次序与字母在字母表中出现的次序相同,且每个字符最多出现1 次。例如,
a,b,ab,bc,xyz 等字符串都是升序字符串。现在对字母表A 产生的所有长度不超过6 的升序
字符串按照字典序排列并编码如下。
1 2 … 26 27 28 …
a b … z ab ac …
对于任意长度不超过6 的升序字符串,迅速计算出它在上述字典中的编码。
-Given the alphabet A by the 26 lowercase letters of the alphabet composed of A = (a, b, ..., z). Generated by the alphabet ascending string refers to the letter string in accordance with the order from left to right appears in the alphabet and letters appearing in the same order, and each character appears a maximum of 1 times. For example, a, b, ab, bc, xyz, etc. are ascending string string. Alphabet A have now all the length of not more than 6 strings of ascending order in accordance with the dictionary and coding sequence is as follows. 1 2 ... 26 27 28 ... ab ... z ab ac ... for any length of not more than 6 strings of ascending quickly calculate it in the dictionary encoding.
- 2023-06-07 02:40:04下载
- 积分:1
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LDPC码的实现源代码,它是用c语言写的。RAR文件的…
LDPC s implement source coding, which is written by c language. The .rar file includes many modules, such as encode, decode, channel, transmitt,and so on. Hope to help you.
- 2022-01-26 02:00:23下载
- 积分:1
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读取鼠标所在位置的单词,sendmessage的实例应用
读取鼠标所在位置的单词,sendmessage的实例应用-The location of the mouse to read words, sendmessage examples of applications
- 2022-07-22 02:04:59下载
- 积分:1
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一个快速写四位bmp位图的c程序
一个快速写四位bmp位图的c程序-a rapid write four bmp bitmap c procedures
- 2023-07-09 02:25:03下载
- 积分:1
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有n个人围成一圈,顺序排号。从第一个人开始报数(从1到3报数),凡报到3的人退出圈子,问最后留下的是原来第几号的那位。...
有n个人围成一圈,顺序排号。从第一个人开始报数(从1到3报数),凡报到3的人退出圈子,问最后留下的是原来第几号的那位。-There are n individuals form a circle,order. The beginning of the first reported from a number of individuals (from 1-3 off), who reported 3 out of the circle of people who asked the last remaining original issue of the first of several that.
- 2022-07-04 05:37:03下载
- 积分:1
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介绍了多种普通元器件的识别判断方法,是一个基础应用手册。...
介绍了多种普通元器件的识别判断方法,是一个基础应用手册。-Introduce a variety of common components to determine the identification method is based on the application of a manual.
- 2023-01-05 10:25:03下载
- 积分:1
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windows格式化的源程序
windows格式化的源程序-windows formatting of the source
- 2022-02-11 23:24:59下载
- 积分:1