RSA加密算法DEMO For Delphi

java ecc java ecc java e-java eccjava eccjava eccjava eccjava ecc

用VERILOG语言实现的数据加密标准代码,在QUARTUS5.1上仿真过-Using Verilog language code of the Data Encryption Standard, in the simulation had QUARTUS5.1

RSA算法 :首先, 找出三个数, p, q, r, 其中 p, q 是两个相异的质数, r 是与 (p-1)(q-1) 互质的数...... p, q, r 这三个数便是 person_key，接著, 找出 m, 使得 r^m == 1 mod (p-1)(q-1)..... 这个 m 一定存在, 因为 r 与 (p-1)(q-1) 互质, 用辗转相除法就可以得到了..... 再来, 计算 n = pq....... m, n 这两个数便是 public_key ，编码过程是, 若资料为 a, 将其看成是一个大整数, 假设 a < n.... 如果 a >= n 的话, 就将 a 表成 s 进位 (s

我用C#做的一个对字符串加密的程序，加密对象为26个字母大小写和0到9的数字，实现的是替代法-I used C# do a strings encryption procedures, encryption targeted at 26 case-sensitive alphanumeric 0-9 and figures to achieve the substitution

While there are many AES cores around, this one is designed with LUT6 based FPGA architecture in mind from day one.  The AES Decryption Core for FPGA implements the decryption portion of the AES (a.k.a. Rijndael) algorithm described in the FIPS-197 specification. Key lengths of 128 / 192 / 256 bits are supported, each with a separate instantiation wrapper. Since the core is designed to take advantage of LUT6 based FPGA archit

loki加密算法-loki encryption algorithm

vb写的rsa加密算法-vb wrote rsa encryption algorithm

对所需要保密的文件进行加密，代码简洁易懂。-right by the need for confidentiality of documents encrypted code easy to read.

使用迭代方程Xn+1=Asin2(Xn-XB)生成混沌序列{Xi}，需输入A和Xb值，不同的值产生不同的加密效果，但是仅在混沌区内的加密效果最好。在Microsoft Visual Studio .NET 2003上调试成功，用C++语言编写-use an iterative equation Xn Asin2 = (Xn- XB) generated chaotic sequence (Xi) need input A and isolate value, different values in different encryption effect, but only in the chaotic region of encryption is the best. In Microsoft Visual Studio.NET 2003 Debugger success C Language

基于一阶Bézier曲线的信息隐藏算法-based Bzier curves of a band of Steganography