这是帮别人做的程序，模拟操作系统中进程控制块（包括多道系统中动态优先级进程调度和动态内存分配），用tc2.0做的，带有图形界面和简陋的控制台。现在把源代码贴出来

基于h323协议的软phone，使用软件编码语言g711,g729等。-h323 agreement on the soft phone, the use of software coding language g711, g729, etc..

好好利用！ 好好利用！ -make good use! M ake good use! M ake good use! M ake good use! Make good use!

试验目的：通过研究Linux的线程机制和信号量实现生产者消费者问题的并发控制 说明：有界缓冲区内设有20个存储单元，放入/取出的数据项设定为1~20这20个整型数。 要求： (1)每个生产者和消费者对有界缓冲区进行操作后，即时显示有界缓冲区的全部内容.当前指针位置和生产者/消费者线程的标识符 (2)生产者和消费者各有两个以上 (3)多个生产者或多个消费者之间须共享对缓冲区进行操作的函数代码。-Test Objective : To study the Linux threading mechanism and signal to producers and consumers to achieve the concurrency control : a boundary buffer There are 20 storage units, Add/remove data items for a set of 20 ~ 20-integer. Requirements : (1) Each producer and consumer sector of the buffer zone is operated, immediately after the sector showed a buffer in its entirety. The current position and producer/consumer threads identifier (2) producers and consumers have two or more (3) A number of producers or many consumers to be shared between the right to operate the buffer function code.

先近先出，时间片轮转，以及优先级的进程调度程序。采用叻C＋＋的编程方法。值得下载。-first-out near first time films rotate, and the process of priority scheduling procedures. Using C++ featuring the programming method. Worth the download.

注意: 1. OS.jar为Java打包可执行文件 2. 由于时间,和界面空间问题,每个进程的资源拥有情况没有详细列明.如果要认真检查 程序的正确性,可以重新编译运行,然后查看Dos界 面下的输出.因为Dos界面下会输出 每个进程的资源情况(包括每个进程对每类资源的最大需求,分配情况,和所欠资源情况. 3. 资源设置中,进程设置应小于100个,资源类数应小于20个.-attention : 1. OS.jar Java package for two executable files. Due to the time and space interface, each process of the availability of resources, no details. If we were to check the correctness of procedures can recompile running, and then checking Dos interface output . because Dos output interface will process each of the resources (including each process for each category of the biggest resources demand, distribution, and outstanding resources. 3. resources set up, the process set up should be less than 100, the resource shall be less than 20.

一个模拟基本进程调度的程序。可以很好的理解进程调度的过程-A simulation of the basic process scheduling program. Can be a good understanding of the process of scheduling the process of

【程序1】 题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？ 【程序2】 题目：企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10 ；利润高 　　　 于10万元，低于20万元时，低于10万元的部分按10 提成，高于10万元的部分，可可提 　　　 成7.5 ；20万到40万之间时，高于20万元的部分，可提成5 ；40万到60万之间时高于 　　　 40万元的部分，可提成3 ；60万到100万之间时，高于60万元的部分，可提成1.5 ，高于 　　　 100万元时，超过100万元的部分按1 提成，从键盘输入当月利润I，求应发放奖金总数？-i don t know!

Stanford iPhone课程配套源码，介绍Address Book的用法。-source code of Stanford iPhone course, demo of how to use Address Book.

资源描述实验一进程的同步.................................................................................................................. 1     1实验目的........................................................................................................................ 1     2实验内容........................................................................................................................ 1 实验二处理机调度.................................................................................................................. 3     1实验目的........................................................................................................................ 3     2实验内容........................................................................................................................ 3 实验三银行家算法...........................................................................................................

Sourcecode of the Linux-011 with detailed chinese annotation,it s verygood and worth reading.