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This is a VHDL language used to write the sub
这是一个用VHDL语言写的分频程序,可用得着-This is a VHDL language used to write the sub-frequency procedures, can be useful
- 2022-09-12 23:15:02下载
- 积分:1
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Phase
相位测量仪的几种方案设计,可供参考,如有需要,就快快下吧-Phase-measuring instrument designed several programs available for reference, if necessary, as soon as possible, are you on
- 2022-03-06 01:38:08下载
- 积分:1
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录入合法的LR(0)文法,将输出LR(0)分析表,并可以对输入的句子进行语法分析输出相应语法分析过程...
录入合法的LR(0)文法,将输出LR(0)分析表,并可以对输入的句子进行语法分析输出相应语法分析过程-Input valid LR (0) grammar, the output of LR (0) analysis table, and can parse the input sentence is the output corresponding grammatical analysis
- 2022-07-07 02:47:16下载
- 积分:1
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本程序是用pascal语言编写的编译原理小程序,包括词法分析,语法分析,语意分析,优化及目标代码生成...
本程序是用pascal语言编写的编译原理小程序,包括词法分析,语法分析,语意分析,优化及目标代码生成-this procedure is used pascal language compiler principles of small programs, including lexical analysis, grammar analysis, semantic analysis, optimization and object code generation
- 2022-01-28 20:34:30下载
- 积分:1
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此代码是一个高级菜单,具有保存、删除、新建、打开和退出的选项…
this code is an advanced menu with options of save, delete, new, open, & exit and it uses colors and highlights-this code is an advanced menu with options of save, delete, new, open, & exit and it uses colors and highlights...
- 2022-02-26 12:20:17下载
- 积分:1
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我做的一个C子集的词法分析器可以分析C语言的一个子集,包括17个关键字以及绝大部分的符号.能正确的报错...
我做的一个C子集的词法分析器可以分析C语言的一个子集,包括17个关键字以及绝大部分的符号.能正确的报错-I do a C subset of the lexical analyzer can be analyzed in a C language subset, including 17 keyword majority of the symbols. Able to correct errors
- 2022-08-03 05:03:58下载
- 积分:1
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elecafns.com
elecafns.com-keilc51教程,又需要的就下吧!-keilc51
- 2022-03-18 18:54:03下载
- 积分:1
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FIR滤波器,经过编译!!!!!!无密码,解压就可用
FIR滤波器,经过编译!!!!!!无密码,解压就可用-FIR filter, after the compiler! ! ! ! ! ! No password, decompression can be used
- 2022-09-18 22:20:03下载
- 积分:1
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词法分析程序,可对以下的C源程序进行分析
词法分析程序,可对以下的C源程序进行分析:main() {int a[12] ,sum for(i=1 i=1 j--){ if(i==j&&i+j==13)sum+=a[i][j] } } printf("%c",sum) }-lexical analysis procedures, right below the C source code analysis : main () (int a [12] [12], the sum for (i = 1 ilt; I = 12) (for (j = 1 JLT; J = 12) Scanf ( "% d", a [i] [j])) for (i = 12 IGT; a = i--) (for (j = 12 IGT; = 1 j--) (if (i == ji j == 13) sum = a [i] [j])) printf ( "% c", sum
- 2022-07-19 15:44:58下载
- 积分:1
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编译原理
编译原理-Compiler Construction Principles
- 2022-09-30 17:20:06下载
- 积分:1