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GNU Make Manual (Chinese translation edition) no need to say more
GNU Make 使用手册(中译版); 没必要多说-GNU Make Manual (Chinese translation edition) no need to say more
- 2023-02-27 21:50:03下载
- 积分:1
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unix 下的写日志
unix 下的写日志-the write log
- 2022-06-26 03:28:28下载
- 积分:1
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GIZA++是自然语言处理的一个非常重要的工具
giza++ 是词语对齐的重要开源工具,做自然语言处理必备的工具-giza++ is an very important tool for natural language processing
- 2022-07-02 03:39:53下载
- 积分:1
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罗技qc摄像头的linux下驱动程序及引用程序
罗技qc摄像头的linux下驱动程序及引用程序-Qc Logitech camera drivers under linux, and quoted procedure
- 2023-05-03 21:05:03下载
- 积分:1
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小型的usb库libusb,通过usb库,通过libusb的接口函数,应用程序可以直接跟usb设备打交道。...
小型的usb库libusb,通过usb库,通过libusb的接口函数,应用程序可以直接跟usb设备打交道。-Small usb library libusb, through the usb library, through the libusb interface functions, the application can deal directly with the usb device.
- 2022-07-01 20:42:03下载
- 积分:1
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Moto A1200 kernel SRC
Moto A1200 kernel SRC
- 2022-08-16 10:27:01下载
- 积分:1
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linux下makefile的书籍,版本为chinesegnumake
linux下makefile的书籍,版本为chinesegnumake-v3.80.pdf-makefile under linux books, version chinesegnumake-v3.80.pdf
- 2022-01-26 01:28:51下载
- 积分:1
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Well
著名图论问题之一。邮递员从邮局出发送信,要求对辖区内每条街,都至少通过一次,再回邮局。在此条件下,怎样选择一条最短路线?此问题由中国数学家管梅谷于1960年首先研究并给出算法,故名。-Well-known graph theory problems. Postman deliver a letter from the post office proceed to require every street within the right area, at least through the time, return to post office. Under these conditions, how to select a shortest route? This issue by the Chinese mathematician Mei Gu tube study in 1960, and gives the first algorithm, hence the name.
- 2022-06-18 09:20:13下载
- 积分:1
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Linux下的蓝牙
linux下的蓝牙
- 2023-08-28 09:45:03下载
- 积分:1
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SD卡的分析源码,可在2440板上运行。是很好的SD卡学习资料...
SD卡的分析源码,可在2440板上运行。是很好的SD卡学习资料-SD
- 2022-07-22 23:12:50下载
- 积分:1