一个绘制柱形图和折线图的ＤＬＬ，里面封装了绘制图表的函数，用于绘制图表...

可以设置窗口透明度及鼠标是否穿透窗体的控件。-Can set the window transparency and mouse controls whether the penetrating form.

delaunay Triangulation

数字图像处理演示程序。为配合《数字图像处理学》一书的出版，便于读者在学习中对本书的主要内容加深理解并增加一些直观的感性认识，以便在更好地理解本书内容的基础上进一步在实践中利用各种图像处理能，特编制了一套实验演示软件。该软件既可以作为教学、演示之用，也可以在实际图像处理中直接应用。由于本软件严格按照软件工程的规范加以制作，并按惯例进行了包装，因此，安装使用极为方便。软件界面采用中文，界面友好、简便，一般不需要特别的专门学习就可以运用。在阅读完该简单说明后，只要动手试一下，便可灵活自如的加以应用。-Digital Image Processing Demonstration Program. To complement the "Digital Image Processing," a book published to facilitate readers in the study of the contents of the book to deepen understanding and increase the number of visual perceptions, in order to better understand the contents on the basis of the practice of using various image processing ability, developed a special experimental demonstration software . The software can be both as a teaching and demonstration purposes, but also in actual direct image processing applications. Since this software in strict accordance with the norms of software engineering to be produced, and the usual packaging, it is extremely easy installation. Chinese software interface, the interface

全屏幕模拟时钟的C源程序 -full-screen clock simulation of C source

该程序封装了贝塞尔曲线的绘制方法――就是Graphics类的DrawBezier()方法。通过他一个不了解贝塞尔曲线数学背景的人都很容易绘制。-Bessel curve of the drawing method-- is the kind of DrawBezier Graphics () method. Through his ignorance Bessel curve of a mathematical background of the drawing is easy.

无闪烁绘制图像，分时画四边形的每个边，希望对大家有帮助-Flicker-free drawing images, time painting each side of quadrangle, in the hope we have helped

指纹识别前处理-----图象分割等包含详尽说明可与我联系QQ43728926-fingerprint identification before processing----- Image segmentation contains detailed information can contact me QQ43728926

Hough变换用来在图象中查找直线。它的原理是：假设有一条与原点距离为s，方向角为θ的一条直线，直线上的每一点都满足方程 s=x*Cosθ+y*Sinθ，利用这个事实，我们可以找出某条直线来。这段程序，用来找出图象中最长的直线。-Hough Transformation is used for searching lines in an image . Here is the principle: Assume there is a line whoes direction is "sita" , and the distance from the origin to this line is s. So each point in this line satisfies the equation : s=x*Cos(sita)+ y*Sin(sita) . We can find out the lines based on this fact. And this programme is to find out the longest line in the image.

zooming an image by using two methods