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均匀圆形阵列天线阵,利用该算法对音乐算法进行估计…
天线阵列为均匀圆阵时,采用MUSIC算法进行DOA估计的源程序。-Antenna array for uniform circular array, the MUSIC algorithm using the estimated DOA of the source.
- 2022-08-09 09:47:19下载
- 积分:1
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Because the speed is relatively slow, suitable for practice, so as not to I am t...
因为速度比较慢,适合练习,免得我是唯一能过关的人。
- 2022-03-23 15:15:13下载
- 积分:1
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该文件是如此的好,你可以用它在任何地方
the document is so good thatyou can ues it anywhere
- 2023-01-25 07:05:04下载
- 积分:1
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字符串的强悍操作,值得学习
字符串的强悍操作,值得学习-string of tough operation, it is worth learning
- 2022-06-26 23:51:54下载
- 积分:1
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使用java编写的足球游戏,非常有意思,适合学习!
使用java编写的足球游戏,非常有意思,适合学习!-prepared by the use of football games, very interesting, suitable for learning!
- 2022-02-12 00:03:50下载
- 积分:1
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关于c++中继承和多态非常好的讲解实例.能够非常快速地学习理解继承。...
关于c++中继承和多态非常好的讲解实例.能够非常快速地学习理解继承。-a program of c++.the best instance of study c++.
- 2022-05-26 11:26:17下载
- 积分:1
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电子制版中常用的封装,包括了平时经常用的大部分元件,省去了很多做封装的时间,可以下来用...
电子制版中常用的封装,包括了平时经常用的大部分元件,省去了很多做封装的时间,可以下来用-Commonly used in e-plate package, including the most frequently used in peacetime components, eliminating the need for a lot of time to do packages can be used down
- 2023-04-08 18:55:04下载
- 积分:1
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本算法使用分治法求解最近点对问题。事先用O(nlogn)时间对x坐标进行排序,使得所有的点是按x坐标从小到大排好序的(x坐标相同时y坐标小的排前),然后取下标小...
本算法使用分治法求解最近点对问题。事先用O(nlogn)时间对x坐标进行排序,使得所有的点是按x坐标从小到大排好序的(x坐标相同时y坐标小的排前),然后取下标小于n/2属于左边的点集PL,取下标大于n/2属于右边的点集PR,即用O(1)时间就可以将规模为n的问题分解为两个规模为n/2的、同类型的子问题。分割完毕之后就可以采用分治法,分别求出PL和PR中的最近点对,最终通过递归实现。-This algorithm uses divide and conquer to solve the problem closest point. Prior to use O (nlogn) time to sort the x coordinate so that all points are based on x coordinates from small to large sorted (x coordinates with the same y coordinates of the small, the top), and then remove the standard is less than n/2 the set of points belonging to the left PL, remove the standard is greater than n/2 set of points belonging to the right of PR, that is to use O (1) time can be the problem size n divided into two size n/2, the same type The sub-problems. Segmentation can be used after completion of sub-rule method, respectively, find the PL and PR in the last points and eventually through the recursion.
- 2022-01-25 16:01:13下载
- 积分:1
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西门子授权,该软件没有把这些东西给西门子。
西门子授权,没这东西西门子的软件用不了的。-Siemens authorization, the software did not take these things for Siemens.
- 2023-03-03 02:00:03下载
- 积分:1
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飞思卡尔试跑程序
飞思卡尔电磁试跑程序,六个传感器,很牛的底文件库,让电磁车飞起来,不一样的感觉,不一样的代码
- 2022-03-18 20:14:43下载
- 积分:1