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是连连看原码,对vc++初学者会有用,大家看看吧
是连连看原码,对vc++初学者会有用,大家看看吧-Is Lianliankan source of vc++ Will be useful for beginners, let us look at it
- 2023-08-28 21:05:04下载
- 积分:1
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此代码为C语言编写的ADC0804源代码,需要的请下载
此代码为C语言编写的ADC0804源代码,需要的请下载-This code for the C language source code of the ADC0804, the need to download the
- 2023-04-08 23:45:04下载
- 积分:1
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GM(1,1)的程序,要用就下啥,可以预测的,里面有详细的说明,很容易看懂的!...
GM(1,1)的程序,要用就下啥,可以预测的,里面有详细的说明,很容易看懂的!-GM (1,1) procedures, to use on the next receivers, and can be predicted, there are detailed explanations, it is easy to read!
- 2022-03-25 18:23:14下载
- 积分:1
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week flight from chee teacher gamma radiation detector Monitoring Program (compi...
从周航慈老师的伽马辐射检测仪监控程序(汇编)改为c的程序-week flight from chee teacher gamma radiation detector Monitoring Program (compilation) to the procedure c
- 2023-07-18 09:40:02下载
- 积分:1
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for:
Root of a Polynomial
for:
Root of a Polynomial
--- --- --- --- --
Time Limit: 1 Second Memory Limit: 32768 KB
--------------------------------------------------------------------------------
A polynomial of degree n has the common form as . Your task is to write a function to find a root of a given polynomial in a given interval.
Format of function
double Polynomial_Root(int n, double c[], double a, double b, double EPS)
where int n is the degree of the polynomial double c[] is an array of n +1 coefficients , , ..., , and of the given polynomial double a and b are the two end-points of the given interval and double EPS is the accuracy of the root.
The function must return the root.
Note: It is guaranteed that a unique real number r exists in the given interval such that p(r) = 0. -for: Root of a Polynomial---------------------- Time Limit: 1 Second Memory Limit: 32768 KB-------------------------------------------------------------------------------- A polynomi
- 2022-09-28 19:15:03下载
- 积分:1
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Credit calculator, Vice c++ source code and project files will certainly be help...
学分计算器,副c++源码和工程文件,一定会很有帮助!-Credit calculator, Vice c++ source code and project files will certainly be helpful!
- 2022-07-09 06:54:24下载
- 积分:1
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在 C# 中的迷宫求解 (最短路径)
介绍了一个简单的技术,以找到一个 2D 的迷宫中两点间最短路径。类似的应用程序在这种情况下使用图,但本文将展示如何,这可以没有头痛的图。它使用类似于广度优先搜索技术。MazeSolver 类商店迷宫作为一个二维整数数组的值 "0" 开放 (可用) 节点和非零这对已关闭的节点 (墙)。如果某条路径将被发现,一种新的二维整数数组创建的路径 PathCharacter 其默认值是 "100"。类也可以跟踪对角的路径,如果它允许这样做
贯穿这篇文章,我们将使用"节点"来引用矩阵 (二维整数数组表示一个迷宫) 的元素。我假设读者是熟悉图和它的术语 (边缘、 节点等)。
- 2023-05-25 08:05:03下载
- 积分:1
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用C语言实现死锁检测
用C语言实现死锁检测-C language Deadlock Detection
- 2022-02-01 15:35:48下载
- 积分:1
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c++程序设计教材(第一版)的源码和答案
书中的例题和书后的练习题答案...
c++程序设计教材(第一版)的源码和答案
书中的例题和书后的练习题答案-c program design materials (first edition) of the source and the sample questions and answers to the book after book answers Exercises
- 2023-07-26 06:20:02下载
- 积分:1
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Can extract a single word (optional fonts) and images extraction tool matrix LCD...
可提取单个字(字体可选)和图片的LCD字模提取工具.-Can extract a single word (optional fonts) and images extraction tool matrix LCD.
- 2022-06-12 03:16:58下载
- 积分:1