BP网络的MATLAB实现,希望对大家有用

2009 软件评测师模拟考试试题 pdf格式-2006 software testing questions pdf

IPv6地址结构技术要求-IPv6 addresses the technical requirements

Matlab学习课件，著名院校老师的。主要是一些代码-Matlab learning courseware, teachers in reputable institutions. Mainly code

/*　　本程序实现的功能： 显示系统时间和日期 　　 该程序主要操作是： 使用了dos的系统调用功能，输入大小写D显示系统当前日期，当输入大小写T输出当前系统时间，当输入大小写Q退出程序，当输入其他字符时，提示错误 。 　　主要算法：将系统时间及日期转化成字符显示，通过堆栈来排序显示，同时涉及到 坐标位置设置的转换。时间和日期的显示都只调用了一个(函数)compute,避免了代码的冗余，尽量做到简洁，同时当一次操作过后，程序处于等待状态，以进行下一次操作，而非自动退出。该程序显示时间时多次调用显示功能，以达到动态效果。*/-/* This program features : The display system time and date of the program is the main operation : the use of the system call dos function, importation case-D display the current date, case-insensitive T when the input output current system, when the input Q withdraw from the case-sensitive procedure, when losers in other characters, suggesting error. The main algorithm : the system date and time into the characters, sorting through the stack to show that involves strategically placed to coordinate conversion. The time and date shown only a call (functions) compute avoid code redundancy, make it simple as possible, and at the same time after the operation, the procedure waits for the next operation, rather than retire. The

用DSP产生六路PWM波来控制永磁无刷直流电机的转动和换向-Road, with DSP generate six PWM wave to control the brushless DC motor rotation and change to the

vhdl ppts giving inflormation of VHDL programming

Calculator program written by DLLs with the math algorithms such as automata and can draw some simple graphs.

很清晰，找了好久，谁有c和指针清晰版的告诉我下啊-Very clear, look for a long time, and who has a clear pointer c and tell me the next version of ah

matlab的函数及指令。最全的指令集和函数集。-matlab functions and commands. The most complete instruction set and function set.

假设检验例题 7.1 设总体 ，其中参数 ， 为未知，试指出下面统计假设中哪些是简单假设，哪些是复合假设： （1） ； （2） ； （3） ； （4） ； （5） . 解：（1）是简单假设，其余位复合假设 -Hypothesis testing for Example 7.1 overall, including parameters, is unknown, pointed out that the following statistical hypothesis test which is a simple assumption, which is a compound hypothesis: (1) (2) (3) (4) (5). Solution : (1) is a simple assumption, the remaining bit composite hypothesis