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goosedump
goosedump --- IEC61850 GOOSE 测试程序-goosedump--- IEC61850 GOOSE Test App
- 2022-05-24 09:57:50下载
- 积分:1
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这是一个用vb编写的小程序,有兴趣的朋友可能DOWN下来
这是一个用vb编写的小程序,有兴趣的朋友可能DOWN下来-This is a little program completed in vb,friends who are interedting in it can diwn it
- 2022-02-24 11:56:51下载
- 积分:1
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matlab 文件实现傅立叶变换算法 实心快速傅立叶变换的算法的代码实现 ,是基于信号处理的一位信号的...
matlab 文件实现傅立叶变换算法 实心快速傅立叶变换的算法的代码实现 ,是基于信号处理的一位信号的-a matlab file realizing the DFT algorithm, realizing FFT algorithm by codes, it is based on the one-dimension signal process.
- 2022-07-19 19:14:46下载
- 积分:1
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[1]
考勤时间=2005
[1]
考勤时间=2005-10-27
员工编号=1
状态=迟到
上班时间(早)=16:59:40
备注=无
[2]
考勤时间=2005-10-27
员工编号=2
状态=迟到
上班时间(早)=16:59:40
备注=无
[3]
考勤时间=2005-10-27
员工编号=3
状态=迟到
上班时间(早)=16:59:40
备注=无
[6]
考勤时间=2005-10-27
员工编号=6
状态=早退
上班时间(早)=上午 18:52:45
备注=无
下班时间(晚)=上午 18:52:45
[5]
考勤时间=2005-10-27
员工编号=5
状态=早退
上班时间(早)=上午 19:01:40
备注=无
下班时间(晚)=上午 19:01:40
[4]
考勤时间=2005-10-27
员工编号=4
状态=早退
上班时间(早)=上午 19:04:14
备注=无
下班时间(晚)=上午 19:04:14
-[1] time = 2005-10-27 employees attendance number = 1 state = late working hours (early) = 16:59:40 Note = No [2] time = 2005-10-27 employees attendance number = 2 status = late working hours (early) = 16:59:40 Note = No [3] time = 2005-10-27 employees attendance number = 3 state = late working hours (early) = 16:59:40 Note = No [6] Attendance time = 2005-10-27 employee ID = 6 state = leave early to go to work hours (early) = 18:52:45 AM Remarks = no working hours (late) = 18:52:45 AM [5] attendance period = 2005-10-
- 2022-08-15 07:26:19下载
- 积分:1
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化简分数到最简
目前只支持质数小于10000的情况
化简分数到最简
目前只支持质数小于10000的情况-Simplification of scores to the most Jane prime number currently only supports the case of less than 10000
- 2023-09-08 10:25:02下载
- 积分:1
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金鹏 s900 6225 TV00578002DABD
金鹏 s900 6225 TV00578002DABD -s900 6225 TV00578002DABD
- 2023-08-13 03:30:08下载
- 积分:1
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企业人事信息管理系统源码/sql 这是基于sql数据库利用vb编写的一个小小的系统程序....
企业人事信息管理系统源码/sql 这是基于sql数据库利用vb编写的一个小小的系统程序.-The company use this to management Human resource
.It is basis on sql code,then use vb to complie
- 2022-03-04 22:20:53下载
- 积分:1
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题目要求:读入两个小于100的正整数A和B,计算A+B。
需要注意的是:A和B的每一位数字由对应的英文单词给出。
输入格式:测试输入包含若干测试用例,每...
题目要求:读入两个小于100的正整数A和B,计算A+B。
需要注意的是:A和B的每一位数字由对应的英文单词给出。
输入格式:测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔。当A和B同时为0时输入结束,相应的结果不要输出。
输出格式:对每个测试用例输出1行,即A+B的值。
输入样例:
one + two =
three four + five six =
zero seven + eight nine =
zero + zero =
输出样例:
3
90
96-Title request: read two positive integer less than 100 of the A and B, calculate A+ B. It should be noted that: A and B each of the figures by the corresponding English words are given. Input format: test input contains a number of test cases, test cases for each line, the format for the " A+ B =" , a string of adjacent spaces in the two intervals. When A and B at the same time 0:00 to the end of input, not output the results of the corresponding. Output Format: For each test case output a line, that is, the value of A+ B. Input sample: one+ two = three four+ five six = zero seven+ eight nine = zero+ zero = output sample: 39,096
- 2022-05-18 03:32:14下载
- 积分:1
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完成堆栈抽象数据类型的顺序、链式表示与实现。实现功能:数值转换,计算器(表达式求值),迷宫求解,判断某个字符串是否是回文...
完成堆栈抽象数据类型的顺序、链式表示与实现。实现功能:数值转换,计算器(表达式求值),迷宫求解,判断某个字符串是否是回文
-Completion of the stack abstract data type of the order, said that with the realization of the chain. The realization of functions: numerical conversion calculator (expression evaluation), to solve the maze to determine whether a string is a palindrome
- 2022-08-07 03:17:15下载
- 积分:1
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使用API VB6源杀进程
Kill Process using api windows VB6 source
- 2022-04-11 22:13:56下载
- 积分:1