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曲线拟合程序
多项式相关系数的计算方法(多项式形式1)
多项式相关系数的计算方法(多项式形式2)
最小二乘法曲线拟合
三次样条插值(自然边...
曲线拟合程序
多项式相关系数的计算方法(多项式形式1)
多项式相关系数的计算方法(多项式形式2)
最小二乘法曲线拟合
三次样条插值(自然边界条件)-polynomial curve fitting procedures correlation coefficient is calculated (the form of a polynomial) polynomial coefficient of correlation Methods (polynomial form 2) least-squares method curve fitting cubic spline interpolation (natural boundary conditions)
- 2022-03-02 20:53:09下载
- 积分:1
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为规范和解决poj 1699
poj 1699的代码和方法说明,个人原创
-the codes and solution for poj 1699
- 2022-06-15 09:10:35下载
- 积分:1
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matlab的演示程序,很有意思,大家可以试一试,欢迎下载
matlab的演示程序,很有意思,大家可以试一试,欢迎下载-Matlab demo program, very interesting, you can try downloading welcome
- 2023-03-18 15:25:03下载
- 积分:1
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算法 排序算法的比较
本代码以插入排序,冒泡排序,选择排序,快速排序,希尔排序等等进行比较,以替换的次数数值的来直观的比较
- 2023-03-15 08:55:04下载
- 积分:1
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A Reader Anti-collision Protocol for RFID-Enhanced Wireless Sensor Networks
资源描述Abstract Considering rapid developments in the technologies of both radio-frequency identification
(RFID) systems and wireless sensor networks (WSN), an integration of the two
technologies may lead to the formation of an RFID-enhanced WSN which would possess
improved functions and capabilities. In the RFID-enhanced WSN, many reader-enhanced
nodes have increasingly been employed. In such networks, RFID data contains a lot of duplication,
because the same tag may be read multiple times, and collision may occur among
readers, while energy constraints are also a serious problem. These three could in turn cause
serious problems. In this paper, we have proposed our CSMA-based algorithm since it is light,
efficiently minimizes all kinds of reader collision, and eliminates the duplicate data. For this
purpose, we have used a separate control channel and a tag ID forwarding mechanism with a
special co
- 2023-05-06 18:20:03下载
- 积分:1
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路径查找代码[vc版本代码]
路径查找代码[vc版本代码]-path search code [vc version code]
- 2023-07-14 23:35:03下载
- 积分:1
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顺序的Gauss消去法
Gauss消去法程序顺序高斯消去法是求解联立线性代数方程的流行方法,许多算法都来自这个方法。这个方法是通过一系列操作实现将增广矩阵简化成上三角矩阵,向量b在这个过程中也被修改,由回代过程得到解向量下x,消去和回代步骤如下:aij=aij-(aik/akk)*akj,k=0,1,2,3,...,(n-2);akk!=0i=(k+1),(k+2),...,(n-1) j=k,(k+1),..,nxn-1=a(n-1)n/a(n-1)(n-1)
- 2022-03-29 00:57:01下载
- 积分:1
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add two number
int main()
- 2022-02-25 10:33:05下载
- 积分:1
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a算法解决八码难题
a算法解决八码难题-a code algorithm to solve eight problems
- 2022-05-24 06:10:31下载
- 积分:1
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This program can determin very accurately the nature of the user input
This program can determin very accurately the nature of the user input
- 2022-08-10 03:45:07下载
- 积分:1