1,与三个秤重仪表PT650通信, 2.与两个温度表AL808通信. 3.同时与FX2n通讯 4.进行配料与混合控制 5.用的是LabView编...

自做的时钟原码，看看吧-done clock since the original code, let"s see it

VHDL 的一个流水灯程序 开发平台Quartusii 使用的延时方法为分频思想

医院门诊管理系统，根据管理员的登录，可以进行医院门诊的管理，对病人进行住院和医用的记录-Hospital out-patient management system, according to the registry administrator, you can out-patient hospital management, hospital patients and medical records

经典编程c语言900个例题，是学习c语言很好的例题。-C programming language 900 Classic Example is a good Example to learn c language.

1）设定字节型变量VAR1的内容为35H，编写程序将VAR1的高4位与低4位分离，分别作为低4位保存在RES1和RES2中,这两个变量高4位置0。 2）设定32位（二进制）数据0E2597455H（注：最高位为E）保存在变量VAR2中，将该变量中的内容算术左移2位，所得结果仍然保存在VAR2中-1) Set the contents of byte variable VAR1 is 35H, the preparation of the program will VAR1 high 4 and low 4 separation, respectively, as a low 4 bits stored in RES1 and RES2, this high-4 position of the two variables 0.2 ) to set the 32-bit (binary) data 0E2597455H (Note: The highest level of E) stored in the variable VAR2 in the contents of the variable arithmetic left two, the result is still stored in the VAR2 in the

This program uses read() and write()-This program uses read () and write ()

我们将用程序来模拟传统的龟兔赛跑问题。我们将采用随机数生成的方法开发这一问题的仿真程序。 再比赛中共设了70个点，每个点代表比赛跑道可能的一个位置。乌龟和兔从第一个点出发，终点是在第70个点上。 时钟按秒来数计。随着时钟的转动，程序能够根据下述规则来调节乌龟和兔子的位置。动物 跑动类型 占用时间 跑动量乌龟 快走 50% 向右3个点 后滑 20% 向左6个点 慢走 30% 向右1个点兔子 睡觉 20% 不动 大后滑 20% 向右9 个点 快走 10% 向左12个点 小步跳 30% 向右1个点 慢后滑 20% 向左两个点 -procedures we will use to simulate the traditional hand problems. We will adopt the random number generator of the development of the simulation program. Another winner set up 70 points, each point represents the runway competition of a possible location. The turtle and a rabbit from the starting point and finish in the first 70 points. According to the clock to a few seconds of dollars. As the clock turned to procedures under the following rules to regulate turtle and the rabbit"s location. Running types of animals occupying volume running time 50% of turtles to leave three points right after sliding 20% six points left walking 30% a point right rabbits sleep 20% Fixed After a 20% slide right nine points to leave 10% left

Acprotect1.10 Build123之C语言篇.chm-Acprotect1.10 Build123 the C language articles. Chm

一个不错考核管理系统，自己写的希望大家多提宝贵意见-a good assessment management system, wrote the hope that we provide more valuable opinions

六层电梯，实现优先级响应，同方向先响应，具体请看源代码-Six-storey elevator to achieve priority response, with the direction of first response, details, please read the source code