自己写C++中的迭代器

演示展示了在delphi使用NtQuerySystemInformation。

C++常用数值算法集4-C Numerical Algorithms used four sets

Windows Mobile 手机应用的红外通信开发示例-Windows Mobile cell phone use infrared communications to develop sample

VB制作的自动取款机取款代码,是小弟我自己做的,有许多不足,请多多指教 -VB produced automatic teller machine withdrawals code, is the younger, I do for myself, there are many deficiencies, exhibitions

设Internet上有N个站点，通常从一个站点发送消息给其他N－1个站点，需依次发送N－1次。 这样从一个站点发布消息传遍N个站点时，可能要较长时间。 设从每一个站点都可以向其他N－1个站点同时发送消息. 当一个站点发布消息给若干个站点后, 设为k个, 已获得消息的这1+k个站点就可以同时发布消息给另外若干个站点, 设为t个, 此后就有 1+k+t 个站点可以同时发布消息，这种发布消息方法应该会缩短消息传遍N个站点的时间。 请您编一个程序, 编程求出从第一个站点开始发布消息传遍N个站点的最短时间。

this book describe Silverlight technic of microsoft.

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected

FLASH自动翻书的效果.跟上次发的那个手动翻书的不一样.可以用在MTV里头.上一次那个可以用来做电子杂志.或者网站.-FLASH automatic book results. With the last of which made the manual book are not the same. Can be used in MTV Erlitou. the last that can be used for the electronic magazine. or website.

IGS文件处理是处理从Solidworks输出的图形信息汇总中提取图形信息来做为其他软件或系统处理的前驱文件-IGS document processing is to deal with Solidworks output from the graphics information to extract summary information to make graphics for other software or systems for treating the precursor document

a document to be studied by students