面向对象程序设计课件，便于vc初学者互相交流学习。仅供参考。...

5个组态软件设计样例(VC++6.0)-5 configuration software design type example (VC 6.0)

工程师必读的十本书 工程师必读的十本书-engineers carefully on the 10 en gineers carefully on the 10 engineers of the 10 required reading book Engineers carefully on the 10

[C语言入门经典(第4版)]整本书的源码！值得推荐！全部是最简单的源码！-[C语言入门经典(第4版)]

中文开发手册，SPRING.pdf。pdf版本 -Chinese development manual, SPRING.pdf

一个个人总结的j2ee学习笔记，供大家参考.-a personal lessons creates study notes, for your reference.

学习AJXA的好教程，适合初学者，更多资料http://www.gishr.com-learning AJXA good guidance for beginners and more information http :// www.gishr.com

TC35I datasheet, make it on, make it off

C++.Primer.Plus第五版中文，初学和精通c++的人都可以看得一本书，写得很经典-C++. Primer.Plus fifth edition of the Chinese, beginner and proficient c++ Can see a book written very classic

在一个划分成网格的操场上，n个士兵散乱地站在网格点上。网格点由整数坐标(x,y)表示。士兵们可以沿网格边上、下、左、右移动一步，但在同一时刻任一网格点上只能有一名士兵。按照军官的命令，士兵们要整齐地列成一个水平队列，即排列成(x,y),(x+1,y),…,(x+n-1,y)。如何选择x 和y的值才能使士兵们以最少的总移动步数排成一列。 实验任务：计算使所有士兵排成一行需要的最少移动步数。-In a grid divided into the playground, n soldiers stood scattered on the grid points. Grid point by the integer coordinates (x, y) express. Soldiers along the edge of the grid, down, left and right moving step, but at the same time any one grid point has only one soldier. In accordance with the officer s command, the soldiers should be neatly列成level queue, that is arranged in (x, y), (x+ 1, y), ..., (x+ N-1, y). How to choose x and y values to make the soldiers with the minimum of the total moves one line up. Experimental tasks: the calculation so that all the soldiers lined up his required minimum moves.

可以与侯捷的书相比的深入浅出java语言程序设计-Hou Jie, the book can be compared with the plain language of java programming language