PIC 16F628 + L6219 在微步模式下步进控制

C函数速查，CHM格式的，平时使用的C语言函数都在里面，比较方便，C++编程也可以使用。-C Function Info, CHM format, usually used in C language functions are in the inside, more convenient, C++ Programming can also be used.

资源描述LPC2478 TFT LCD控制器源代码。同时PLL、GPIO和SDRAM的初始化。初始化后，TFT充满固体的颜色和图像。

针对区域立体匹配计算量大实时性差的困难,分析了相关匹配算法的实际工作过程,采用消除冗余因子和M2C滤 波、多级分辨率匹配减小计算复杂度,对算法结构进行了改进和优化,并利用超线程和D65/EF技术对算法进行了加速,提出 了一种实时区域匹配算法。对算法进行实验,结果表明算法符合了视觉导航的准确性和实时性要求,并且对于提高其他区域 匹配算法实时性也具有重要借鉴意义。-Stereo matching for the regional real-time calculation of a large quantity of poor difficulties, analysis of the relevant matching algorithm the actual work process, used to eliminate redundancy factor and M2C filtering, multi-resolution matching to reduce the computational complexity of the algorithm structure to improve and optimize the and take advantage of Hyper-Threading technology and D65/EF accelerated algorithm, a regional real-time matching algorithm. Algorithm experiment results show that the algorithm is consistent with the accuracy of visual navigation and real-time requirements, and improve in other regions for real-time matching algorithm is also an important reference.

软件工程设计报告 JAVA设计 教室管理系统-JAVA software engineering design report design classroom management system

随机信号课件 大家相互学习学习 有意见也请大家提出来 -Random signal courseware to learn from each other U.S. study has also asked people to put forward their views to

资源描述delphi_7实用编程100例，许多的案例，包括打印，图形图像，数据库等

该项目致力于securised开门使用。我们的Objectif是实现一个洞的解决方案，让只有被授权的人通过门上。它可以在劳动或安全设施，它分为两个部分来使用：第一个是一个面部识别PROGRAMM，让知道，如果这个人是有权通过或没有（如果他有atribut数据库上的通的“真”值存在）。我们使用的OpenCV和JavaCV作为包装第二部分是一个嵌入式系统将控制门开口。它从由所述第一部分中提供的所述一个值的开口或不决定。我们将使用STM32嵌入式卡我们实际上是工作的两个部分，这是我们的前进在第一部分上的释放

基于Delphi的制药企业ERP管理决策系统.pdf-Delphi-based pharmaceutical company ERP system, management decision-making. Pdf

对当前很火的网络电话的分析，分析internet peer to peer telephony protocol-fire right now is the telephone network analysis, peer to peer internet telephony protocol

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected