in VC6.0 platform. From this program can understand C++ virtual function of the...

进程状态转化程序实现，这是在学习操作系统过程的时候，我做的一个课程实验-process into a state program, which is in the process of learning the operating system, I do an experimental courses

在vc++平台下，用分支限界法和回溯法实现的旅行售货员问题。经本人测试运行无误，包括运行文档。-In vc++ Platform, using branch and bound and backtracking realize the travel salesman problem. After I run the correct tests, including the operation of the document.

步进电机控制，能很好地学习单片机控制步进电机的原理及应用。-stepper motor control, can be a good learning SCM stepper motor control and application of the principle.

输入完成数学表达式例如1+(5/2)*3 即可计算出结果 支持运算符:+ - * / () ^-Enter the complete mathematical expression such as 1+ (5/2)* 3 to calculate the results support the operator:+-*/() ^

封装非终结符集合的类Vn，可以求出 FIRST集和FOLLOW集。-Package of non-terminal symbol set of classes Vn, you can find the FIRST sets and FOLLOW sets.

运动控制卡应用事例程序，对编程人员很方便。采用动态连接库方法-Control card application software

Face Detection from OpenCV

应用背景这是一个rdos.exe（应用） ；简单的和可怕的使用这仅供测试不要用于非法活动下载的端口扫描器关键技术12345678910qwertyuiopasdfghjklzxcvbnmn。/”；] [ ` =。，一；asdasaaasdasda

简单的用于获取网卡信息的源代码，有点乱IP+MAC-Simple card information for access to the source code, somewhat arbitrary IP+ MAC

应用背景关键技术子程序collesion（U，V，F，信，Rho，欧米茄，W，CX，CY，n，m）真正的F（0:8,0：N，0米）真正的信（0:8,0：N，0米），ρ（0 N，0米）真正的W（0:8），CX（0:8），CY（0:8）真正的U（0 N，0米），V（0 N，0米）我= 0，N做J = 0，MT1 = U（i，j）×U（I，J）+ V（i，j）* V（I，J）做K = 0.8T2 = U（i，j）* CX（K）+ V（i，j）* CY（K）方程（K，I，J）=ρ（i，j）×W（k）*（1 + 3 + 4.50 * * T2 T2 t2-1.50 * T1）F（K，I，J）=ω*信（K，I，J）+（1。欧米茄）* F（K，I，J）结束做结束做结束做返回结束