determinante EM C

简单的mobile程序 c#做的我从网上下载 不知对大家有没有用 或者对编程者有无帮助-simple mobile c# procedures do I downloaded from the Internet do not know right have we to use or whether to help programmers

取bios信息， -Check bios information

http协议下载文件vc实现,可以做网页图片采集，内容采集解压密码www.39g.com-http protocol to download files vc achieve, you can do page image acquisition, content acquisition unzip password www.39g.com

实现双服务器的心跳探测，支持udp和串口。 快平台的tcp，udp类。-Dual server heartbeat detection, and support for serial udp. Express platform tcp, udp category.

一个简单的聊天程序 网络编程-A simple chat program network programming

基于Socket的TCP模块，支持多线程-Socket Based on the TCP module, support for multi-threaded

Client程序同样分别创建一个TCP socket 和一个UDP socket，首先client使用TCP socket连接TCP Server。 连接成功后显示提示信息； 然后client端向TCP Server发送“GET UDP PORT”字符串，Server收到后向client回送自己的UDP Server 端口号（即Client端仅知道TCP Server的端口号而不知道UDP Server的端口号）； client在收到UDP Server的端口号后, 为用户显示3个选项： 1．“Get current time（TCP）”服务器时间 2．“Echo Mode（UDP）”回显6 3．“Exit the program”. -Client program also creates a TCP socket, respectively, and a UDP socket, the first client to use TCP socket connection TCP Server. After a successful connection displays a prompt message and then client-side to the TCP Server sends " GET UDP PORT" string, Server receipt back to the client to send their UDP Server port number (ie, Client-side only to know the TCP Server" s UDP port number do not know Server" s port number) client received UDP Server port number, in order to the user three options: 1. " Get current time (TCP)" server time 2. " Echo Mode (UDP)" echo 63. " Exit the program" .

C#版的聊天室，含主机与客户端，登录界面类似-C# Version of the chat room, including host and client, login screen similar to

一个值得研究的下载程序， 来自于网络！-one worth studying download from the Internet!

分隙ALOHA: 该协议下，用户在产生帧后总是等到下一帧时开始时才发送，所以，对于结构FrameTime_struct，其m_Frame[i]（相对时间）总是为零。发生冲突后同样等待一个随机时间重发。 所以只要满足当前帧时只有一帧发送，就可以发送成功，而不需考虑上一帧时的情况。 -points gap ALOHA : under the agreement, users always have a frame after frame until the next time when this started, so that the structure FrameTime_struct, m_Frame [i] (relative to time) always zero. After the conflict the same time waiting for a random re-issued. Therefore, as long as the current frame to meet only one this, we can successfully sent, and not considering one at the situation.