用vc＋＋开发的一个经典程序：Dice。自己开发的，可以两个人玩儿。...

有关字符处理及获取机器日期的一些源程序- Related character processing and gain machine date some source programs

一个模仿操作系统的页面调度算法，模拟了调试的基本操作。-a copy of the operating system pages scheduling algorithm, a simulation testing the basic operation.

配合刚刚上传的TOOLBOX_calib,是进行标定的标定图-With just uploaded TOOLBOX_calib, calibration is the calibration graph

运用VC++和OPENGL编写的一个实现俄罗斯方块的小程序-VC and OpenGL application prepared by the Russian box to achieve a small procedure

基于asp的博客系统+论文(代码齐全)经过调试-Asp" s blog-based system+ thesis (code range) after adjustment

关于在LINUX下的计算日期时间的代码.计算N天后,或者N天前的日期.-LINUX on the date of the calculation time code. Calculation N days, or N days before the date.

运行环境 TC2.0 w,s,a,d控制方向, 逗号和句号控制力量,空格发杆 本来还可用鼠标控制,因为要用一个"mouse.h",所以去掉了-runtime environment WITH TC 2.0 w, s, a, d to control direction, the comma and full stop controlling forces, space-could have also been made with the mouse control, because we are a "mouse.h", removed the

MFC Graphics Tablet Test Application

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

提供使用扩展内存XMS完成大数组的类-for use XMS memory expansion to be completed array of categories