Robot code to control the surveyor robot

线性方程组的计算，采用的是高斯消元法来实现的。只有主要的算法代码，没有写主函数(Calculation of linear equations using the Gauss elimination method to achieve. Only the main algorithm code, did not write the main function)

3D游戏编程大师技巧1-16章源码，配书的没有改动(3D game programming skills master code chapter 1-16)

【实例简介】51ST7789

C语言程序适合刚开始学习步进电机的人，利用单片机控制步进电机的运转(Controlled stepper motor running)

单片机1260Sc5a 的ad 采集电压，带详细注解，适合初学者哦！(The microcontroller 1260Sc5a ad collection voltage, with detailed notes, suitable for beginners Oh!)

STM32 modbus协议 从机程序

说明：  c++音乐播放器原理示例代码，帮助新手入门音乐播放器(A sample code for the principle spout of c-music player to help novices get started with a music player)

C#Web开发 使用DSOFramer插件实例。(C# Web developers use DSOFramer plug-in instance.)

读取jpeg图片数据并输出到txt文本中，再从txt文本中读取数据生成图片(Reading image data and outputs to txt, and then read the data generated image txt text)

VC++枣子穿纽游戏源码，类似扫雷游戏的界面，不过玩法有点不一样，游戏源代码在vc++6下编译通过，你应该通过源代码能看出些玩法来。 　　相关资料：在本游戏中，你将作为一名裁缝，将尽可能多的纽扣穿成一个闭合的路线。游戏初始有 15 个纽扣，随着时间的增加，纽扣数目也增加，当达到70个时游戏即结束。只能在有纽扣的点穿线，且只能在水平方向或竖直方向穿线。线可交叉，但有纽扣的点不能交叉连接。 　　透露点秘诀：要尽可能使连线长且该连线上的纽扣数多。(VC++ source code dates to wear new game, the game interface similar to mine, but a bit different from playing the game in the source code to compile under vc++6 passed through the source code you should be able to see more options. Relevant information: in this game, you will serve as a tailor, will be wearing buttons as much as possible into a closed line. Game initial 15 buttons, an increase over time, increase the number of buttons, when the 70 hours to reach the end of the game that is. Buttons can only point in the threading, and only in the horizontal direction or vertical direction of threading. Lines cross, but the buttons can not be cross-connect point. Point revealed the secret: To the extent possible, so long and the connection to connect on a few more buttons.)