Motorola MCU MC68HC908 companies achieve SCI function of the sample program, C l...

关于来电识别的程序-on caller identification procedures

model of induction motor

电机调速的控制程序，你可以通过这个程序来设定参数，通过反馈就可以控制速度了啊！-of motor speed control procedures, you can use this procedure to set parameters, feedback can control the pace of their ah!

18B20在msp430下的应用 没有错误，运行相当完好 且兼备简洁易用的优点-18B20 in MSP430 applications under the error-free, running very well and the advantages of both simple and easy-to-use

显示驱动芯片HT1621的C51底层程序-display driver chip HT1621 the bottom procedures C51

一个在8051F120上实现的免费的实时系统-a 8051F120 in achieving the free real-time systems

开发硬件电路需要用到液晶显示模块1602的用户必备。调试实验源程序第四部分。-Hardware needed to develop liquid crystal display module 1602 required the user. The fourth part of the experimental source code debugging.

51单片机开发与应用技术详解（珍藏版）光盘中源代码 《51单片机开发与应用技术详解(含光盘1张)》全面详细地讲述了单片机的原理、编程指南及应用案例，其中51系列单片机的编程部分是《51单片机开发与应用技术详解(含光盘1张)》的重点。《51单片机开发与应用技术详解(含光盘1张)》分为5篇38章。首先介绍了51系列单片机的开发概述及单片机的基本结构，接着介绍了单片机的汇编程序设计语言，然后介绍了单片机C51语言的程序设计，随后结合单片机的指令系统及各个功能部件详细讲解了单片机的编程操作，以及单片机硬件资源的仿真和程序调试。《51单片机开发与应用技术详解(含光盘1张)》最后还给出了在各个领域中常用到的一些典型案例，供读者在学习和工作中参考。 《51单片机开发与应用技术详解(含光盘1张)》知识点覆盖全面、结构安排紧凑、讲解详细、实例丰富。对于51系列单片机的初学者，通过《51单片机开发与应用技术详解(含光盘1张)》可以快速掌握单片机的程序设计。《51单片机开发与应用技术详解(含光盘1张)》对具有一定开发经验的设计人员，也有很好的参考价值。- 51 MCU Development and Application of Technology Xiang Jie (Limited Edition) CD-ROM Source Code "51 MCU Development and Application of Technology Xiang Jie (including CD-ROM 1)" fully explain in detail the principles of the MCU, programming guide and application of case in which 51 series microcontroller programming part "51 single film machine development and application technology Xiangjie (including CD-ROM 1) "focus. "51 MCU Development and Application of Technology Xiang Jie (including CD-ROM 1)" is divided in

利用C8051F单片机控制的铣床模型（直线圆弧插补算法）-C8051F MCU using milling machine model (straight line circular interpolation algorithm)

高速电路信号完整性问题，有一定的参考价值-Based on the Signal Integrality theory, the key problem met during signal processing module design and its solution is given