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编程环境为VC,图形化操作,可以实现光驱的打开,关闭。最小化此程序时能够托盘化显示。...
编程环境为VC,图形化操作,可以实现光驱的打开,关闭。最小化此程序时能够托盘化显示。-Programming environment for the VC, graphical operation, the drive can be opened, closed. Minimize to tray when the program display.
- 2023-06-15 23:10:03下载
- 积分:1
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bsdsort
bsdsort-1.0.tar BSD排序
- 2022-01-30 12:33:23下载
- 积分:1
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一个实时温度曲线示例的实现代码(坐标抽不动,曲线动)
一个实时温度曲线示例的实现代码(坐标抽不动,曲线动)-Example of the realization of a real-time curve
- 2022-10-05 14:45:03下载
- 积分:1
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用vc实现的一个画图程序,画一个圆形和方形。本来可以画三角形,不过没有设定。同时程序中设了timer用来使图形移动,加一点趣味罢了!...
用vc实现的一个画图程序,画一个圆形和方形。本来可以画三角形,不过没有设定。同时程序中设了timer用来使图形移动,加一点趣味罢了!-vc achieved with a drawing, and painting a circle and a square. Triangle could have been painted, but not set. While proceedings timer used to set up a mobile so that the graphics and some fun too!
- 2022-02-07 03:04:24下载
- 积分:1
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一个自己编写的已对话框为界面的 计算器程序 能完成基本的计算功能...
一个自己编写的已对话框为界面的 计算器程序 能完成基本的计算功能-one has been prepared by its own dialog interface for the calculator program can be completed basic computing functions
- 2022-03-01 23:35:41下载
- 积分:1
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网络与通信源程序.zip
网络与通信源程序.zip-networking and communications source. Zip
- 2022-03-11 23:42:25下载
- 积分:1
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To test the document should be the first to start UdpServer server
、测试该文件时应首先启动UdpServer的服务器端,接着启动myUdpClient的客户端软件。
3、在myUdpClient项目文件中myUdpClient.cs文件的56行为连接到远程服务器端的IP地址,这里为本地IP地址,实际使用时应相应更改。
以上软件是需要注册才能长期正常使用的软件,请大家支持正版软件的使用-To test the document should be the first to start UdpServer server-side, and then start the myUdpClient client software. 3, myUdpClient project documents myUdpClient.cs file 56 acts to connect to the remote server-side IP address, where the local IP address, the actual use should be changed accordingly. The above software is required to be registered in order to long-term normal use of the software, please support the use of genuine software
- 2022-07-20 00:11:13下载
- 积分:1
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监控状态的小应用程序
监视器监听状态的小的应用程序-monitors monitor the state of small applications
- 2023-05-04 00:30:03下载
- 积分:1
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一个捕捉屏幕鼠标位置的源程序,包括所有的源码
一个捕捉屏幕鼠标位置的源程序,包括所有的源码-Capture the screen of a mouse the location of source, including all of the source
- 2022-09-18 18:55:03下载
- 积分:1
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约瑟夫环(Joseph)问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始人选一个正整数作为报数上限值m,从...
约瑟夫环(Joseph)问题的一种描述是:编号为1,2,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始人选一个正整数作为报数上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从它在顺时针方向的下一个人开始重新从1报数,如此下去,直至所有人全部出列为止。试设计一个程序求出出列顺序-Joseph Central (Joseph) a description of the problem is: numbered 1,2, ..., n of n individuals according to a clockwise direction around a circle, each holding a password (positive integer). The beginning of a positive integer as a candidate at a number of upper limit of m, from the first individual to embark on the clockwise direction since the beginning of the order of 1 is reported the number of stops required to report back at a few m. Those who reported m out of his password as the new value of m, in a clockwise direction from the next person to start off again from the 1, and so on, until all that out until all. Try to design a procedure to derive the column order
- 2022-02-10 01:58:28下载
- 积分:1